Ask question

Ask question

All categories

3 years ago

14

5839%29 step by step solve

1 answer:

valkas [14]3 years ago

8 0

The following answer is 10

You might be interested in

Solve the following equation. | x + 3 | = 4

Lelechka [254]

Answer:

x1= -7 , x2= 1

Step-by-step explanation:

8 0

3 years ago

2.952 + 39.24 = <br>A: 42.192<br>B: 68.76<br>C: 6.876<br>D: 687.6<br>E: 36.288<br>F: 42.76

kirill [66]

Answer:

The answer to this question is A

4 0

3 years ago

Read 2 more answers

Thirty work orders are selected from a filing cabinet containing 500 work order folders by choosing every 15th folder. which sam

Andru [333]

It is Systematic sampling

5 0

3 years ago

The functions f(x) and g(x) are described below: f(x) = 7x + 9 g(x) = 7x −4 The graph of g(x) is obtained by shifting down the g

Slav-nsk [51]

Correct Answer:
Option A

Solution:

f(x) = 7x + 9
g(x) = 7x - 4

We can re-write g(x) as:

g(x) = 7x + 9 - 13

Since 7x+9 is equal to f(x), we can write:

g(x) = f(x) - 13

This relation shows that g(x) is obtained by shifting f(x) 13 units vertically down. So the correct answer is option A.

6 0

3 years ago

If a ship's path is mapped on a coordinate grid, it follows a straight-line path of slope 3 and passes through point (2, 5).

Ugo [173]

Part A: The equation of the ship's path is $y=3x-1$

Part B: The two ships sails perpendicular to each other.

Explanation:

Part A: It is given that $m=3$ and point (2, 5)

Substituting these in the slope intercept form, we have,

$y-y_{1}=m\left(x-x_{1}\right)$

$\begin{aligned}y-5 &=3(x-2) \\y-5 &=3 x-6 \\y &=3 x-1\end{aligned}$

Thus, the equation of the ship's path in slope intercept form is $y=3x-1$

Part B: The equation of the second ship is $x+3 y-6=0$

Let us bring the equation in the form of slope intercept form.

$\begin{aligned}3 y &=-x+6 \\y &=-\frac{1}{3} x+2\end{aligned}$

Thus, from the above equation the slope is $m=-\frac{1}{3}$

To determine the two ships sailing perpendicular to each other, we have

$m_{1} \times m_{2}=-1$

where $m_{1}=3$ and $m_{2}=-\frac{1}{3}$

$\begin{aligned}3 \times-\frac{1}{3} &=-1 \\-1 &=-1\end{aligned}$

Since, both sides of the equation are equal, these two ships sails perpendicular to each other.

3 0

3 years ago