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3 years ago

True or false mobile devices need to work within limited screen space

Computers and Technology

2 answers:

Mama L [17]3 years ago

5 0

Answer

TRUE

Explanation

Mobile devices are portable computing devices such as a smartphones or tablet computer.These devices are designed to be extremely portable, and they can often fit in your hand and they are powerful enough to do many of the same things you can do with a desktop or laptop computer.Mobile devices need to work within limited screen space.

eduard3 years ago

3 0

A phone may have a 4 inch screen and so it cant just extend to 5 inches. So it would he true

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Which of the following is a quick way to restore the arrow pointer after you have used it for drawing?

Oxana [17]

A quick way to restore the arrow pointer after you have used it for drawing is to press the esc key. The esc key is used for any of the different functions, as to interrupt or cancel the current process or running program, or to close a pop-up window.

7 0

3 years ago

cout << "Part 1" << endl; // Part 1 // Enter the statement to print the numbers in index 4 and index 9 // put a spac

Margarita [4]

Answer and Explanation:

#include <iostream>

using namespace std;

int printEven(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2==0)

{

count++;

cout<<array[i]<<" ";

}

return count;

}

void printAll(int array[],int n)

{

for(int i=0;i<n;i++)

{

cout<<array[i]<<" ";

}

int computeTotalOdds(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2!=0)

{

count++;

}

return count;

}

int main()

{

int array1[20] = {3, 18, 1, 25, 4, 7, 30, 9, 80, 16, 17};

int numElements = 11;

cout << "Part 1" << endl;

cout<<array1[4]<<" "<<array1[9];

cout << endl;

cout<<array1[0]<<" "<<array1[8];

cout << endl;

array1[2]=12;

cout << "\nPart 2" << endl;

printAll(array1,numElements);

cout << "\nPart 3" << endl;

int evens;

evens=printEven(array1,numElements);

// This will print the number of evens in the array.

cout << endl << evens;

cout << "\nPart 4" << endl;

int total;

total=computeTotalOdds(array1,numElements);

cout << endl << total;

return 0;

}

3 0

3 years ago

Declare a typedef struct named jumper_t that will have four parts: character array name that is 16 in length, double array of tr

Maurinko [17]

Answer:

The typedef struct is as follows:

typedef struct jumper_t {

char name[16];

double tries[N_TRIES];

double best_jump;

double deviation;

} jumper_t;

The declaration of jlist is:

jumper_t jlist[10];

Explanation:

This defines the typedef structure

typedef struct jumper_t {

The following declares the variables as stated in the question

char name[16];

double tries[N_TRIES];

double best_jump;

double deviation;

}

This ends the typedef definition

jumper_t;

(b) The declaration of array jlist is:

jumper_t jlist[10];

6 0

3 years ago

The read/write heads of a hard disk gently rest on the hard disk platters in order to read and write the data.

noname [10]

The answer is FALSE because the interior of commercial Hard disk drive is with stack of magnetic disks (platters) containing the user’s data and a rotating arm supporting the magnetic heads. The rotating arm is moved by the torque generated by a voice coil motor (VCM) mounted at one end of the arm. Data read/write operations rely on the capability of the governing unit of the HDD to maintain the magnetic read/write heads as close as possible to center of the desired track. Typically, reliability of data reading and writing is guaranteed when the head is kept within 5% of the track pitch from the track center. This means that the accuracy required for the head positioning is in the range of a few tens of nanometers.

6 0

4 years ago

Write a function that checks whether two words are anagrams. Two words are anagrams if they contain the same letters. For exampl

Masteriza [31]

Answer:

def isAnagram(s1, s2):

list1=s1

list2=s2

sortedlist1 = sorted(list1)

sortedlist2 = sorted(list2)

if sortedlist1 == sortedlist2:

print(list1+ " and "+list2+ " are anagram")

else:

print(list1+ " and "+list2+ " are not anagram")

Explanation:

Here is a call to the function isAnagram():

list1 =input("Enter String1 ")

list1 =input("Enter String2 ")

isAnagram(list1,list2)

Attached is the run and output for this program

4 0

3 years ago