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labwork [276]
3 years ago
6

The acceleration due to gravity of the earth is 9.81 m/s2 and the acceleration due to gravity of the moon is 1.625 m/s2. If your

mass is 70 kilograms, calculate your weight on BOTH the earth and on the moon.
Physics
1 answer:
Viktor [21]3 years ago
3 0

Answer:

686 N

113.75 N

Explanation:

On Earth:

W= mg

= 70 x 9.8

= 686 N

On Moon:

W= mg

= 70 x 1.625

= 113.75 N

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Talja [164]
<h2>Hello!</h2>

The answer is A.   the principal energy level

<h2>Why?</h2>

The principal energy level or principal quantum number n, tell us about the position of an determined electron in the energy levels relative to the greater average distance of an electron from the nucleus, the larger the value of n and the higher its energy.

The principal energy levels contains n sublevels, n^{2} orbitals and 2n^{2} electrons.

For example, the number 1, has one orbital which is contained in a energy sublevel, its called s orbital, and it's just an orbital with 2 electrons.

Have a nice day!

7 0
3 years ago
Read 2 more answers
Nathan has a car that accelerates at 5 m/s2. If the car has a mass of
zhannawk [14.2K]

Answer:

F = 5000 [N] or 5 [kN]

Explanation:

In order to solve this problem we must take into account Newton's second law, which tells us that the sum of all forces applied on a body must be equal to the product of the mass of the body by its acceleration.

F = m*a

where:

F = force [N]

m = mass = 1000 [kg]

a = acceleration = 5 [m/s^2]

F = (1000*5)

F = 5000 [N] or 5 [kN]

5 0
3 years ago
Ik you didnt do the lab but like idek...
serious [3.7K]

Answer:

Speed and direction affect pitch.

4 0
3 years ago
A 12.0 kg object is attached to a cord that is wrapped around a wheel of radius 10.0 cm. the acceleration of the object down the
olganol [36]

 a) We use the formula:

T = [g sinθ – a] * m

where g is gravity, θ is the angle, a is acceleration, m is mass

T = [9.81 sin37 - 2.00] * 12 = 46.85 N <span>

b) We use the formula for moment of interia:</span>

I = T * r² / a

I = 46.85 * 0.10² / 2.00 = .2343 kg∙m² <span>

c) The formula we can use here is:</span>

w = α * t = (a/r) * t

w = (2/.10) * 2

<span>w = 40 rad/sec</span>

6 0
3 years ago
The acceleration of gravity on the moon is about 1.6 m/sec 2. An experiment to test gravity compares the time it takes objects t
Valentin [98]
The answer is <span>b. 6.1 times as long
</span>
Step 1: Calculate the time <span>it takes objects to reach a speed on the Moon.
</span>Step 2: Calculate the time it takes objects to reach a speed on the Earth.
Step 3. Divide the time on the Moon by the time on the Earth.

Use the formula: v2 = v1 + at
v2 - the final velocity
v1 - the initial velocity
a - gravitational acceleration
t - time

Step 1.
Moon:
<span>v1 = 0 (because it is free fall)
v2 = 10 m/s
a = 1.6 m/s</span>²
t = ?
______
v2 = v1 + at
10 = 0 + 1.6t
10 = 1.6t
t = 10/1.6
t = 6.25 s


Step 2.
Earth:
v1 = 0 (because it is free fall)
v2 = 10 m/s
a = 9.81 m/s²
t = ?
______
v2 = v1 + at
10 = 0 + 9.81t
10 = 9.81t
t = 10/9.81
t = 1.02 s


Step 3:
6.25 s / 1.02 s = 6.1 s
7 0
3 years ago
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