A greyhound's velocity changes from rest to 19 m/s in 2 seconds. What is the greyhound's average acceleration?

If the half-life of a 2.0 gram sample of a radionuclide is 15 hours, then the half-life of a 1.0 gram sample of the same radionu

Lerok [7]

7.5 hours or 450 minutes. 15/2=7.5

5 0

3 years ago

Suppose you take

kati45 [8]

Answer:

a current will be induced.

Explanation:

4 0

3 years ago

Read 2 more answers

Determine the moment of the force at AAA about point PPP. Use a vector analysis and express the result in Cartesian vector form.

Dimas [21]

Answer:

τ = 0

Explanation:

At the moment it is defined

τ = F x r

In tete case they give us the strength and position in Cartesian form, so it is easier to solve the determinant

τ = $\left[\begin{array}{ccc}i&j&k\\F_{x}&F_{y}&F_{z}\\x&y&z\end{array}\right]$

Let's apply this expression to the exercise

a) P = (-6 i ^ -3j ^ -6 k ^) m

F = (-6 i ^ -3j ^ -6k ^) 103 N

τ = $\left[\begin{array}{ccc}i&j&k\\-6&-3&-6\\-6&-3&-6\end{array}\right]$

τ = i ^ (3 6 - 3 6) + j ^ (6 6 -6 6) + k ^ (6 3 - 3 6)

τ = 0

b) P = 24i ^ + 8j ^ + 9k ^

F = 24i + 8j + 9k

τ = i ^ (72-72) + j ^ (216-216) + k ^ (24 8 - 8 24)

τ = 0

c) P = -6i + 6j-4k

F = -6i + 6j-4k

τ = i ^ (24-24) + j ^ (- 24 + 24) + k ^ (-36 + 36)

τ = 0

.d) P = 24i-8j + 9k

Let's change the sign of strength

F = -24i + 8j-9k

Tae = (I j k 24 -8 9 -24 8 -9)

Tae = i ^ (72 -72) + j ^ (- 216 + 216) + k ^ (192-192)

Tae = 0

8 0

3 years ago

ILL GIVE BRAINLIEST!! please help and answer correctly!

Hunter-Best [27]

Answer: B

Action and reaction forces act on the same object and go to the same direction

6 0

3 years ago

A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m 14, start fraction, start text, m, en

Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

a

=

Change in time

Change in velocity

=

Δt

v

f

−v

i

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

f

v, start subscript, f, end subscript, initial velocity v_iv

i

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

=

Δt

v

f

−v

i

=

3.5s

−21

s

m

−(−14

s

m

)

=−2.0

s

2

m

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

s

2

m

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0

3 years ago