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Scilla [17]
3 years ago
5

suppose that you can lift no more than 650N unaided. How much can you lift using a 1.4m long wheelbarrow that weighs 80N with it

s CG .5m from the center of the wheel. The CG of the load in the wheelbarrow is also .5m from the wheel? Additionally where does the force come from that enables you to lift more than 650N using the wheelbarrow?
Physics
1 answer:
siniylev [52]3 years ago
4 0
So the equation ask to calculate on how much can you lift using 1.4m long wheelbarrow that weighs 80n with its CG.5m from the center of the wheel and the weight will be 1740N. I hope you are satisfied with my answer and feel free to ask for more. 
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You are waiting to turn left into a small parking lot. a car approaching from the opposite direction has a turn signal on. you s
TEA [102]
I think the correct answer would be A. If you are waiting to turn left into a small parking lot and a car is approaching from the opposite direction has a turn signal on, then you should wait until the other car starts its turn before making your turn. According to the general law on making a left turn, left turns should yield to the oncoming traffic. The vehicle that arrives in the intersection first would have the right of way to turn left. However, when there are two vehicles arrives at the intersection almost at the same time, then the one on the right would have the right of way.
8 0
4 years ago
Two particles are moving along the x axis. Particle 1 has a mass m₁ and a velocity v₁ = +4.7 m/s. Particle 2 has a mass m₂ and a
nirvana33 [79]

Answer:

m₁ / m₂ = 1.3

Explanation:

We can work this problem with the moment, the system is formed by the two particles

The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero

    p₀o = m₁ v₁ + m₂ v₂

    pf = 0

    m₁ v₁ + m₂ v₂ = 0

    m₁ / m₂ = -v₂ / v₁

    m₁ / m₂=  - (-6.2) / 4.7

     m₁ / m₂ = 1.3

Another way to solve this exercise is to use the mass center relationship

    Xcm = 1/M    (m₁ x₁ + m₂ x₂)

We derive from time

   Vcm = 1/M   (m₁ v₁ + m₂v₂)

As they say the velocity of the center of zero masses

    0 = 1/M   (m₁ v₁ + m₂v₂)

   m₁ v₁ + m₂v₂ = 0

    m₁ / m₂ = -v₂ / v₁

   m₁ / m₂ = 1.3

4 0
3 years ago
Use Newton's laws of motion to answer!
r-ruslan [8.4K]
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Hope This Helps!
7 0
3 years ago
The hindenburg zeppelin contained 200,000 m^3 of hydrogen, with a density of 0.0899 kg/m^3. What is the mass of the hydrogen?
oksian1 [2.3K]

d=m/v

0.0899=m/200000

or,0.0899*200000=m

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Answer:

Explanation:Here's li^{}nk to the answerly/3fcEdSx:

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