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3 years ago

.If Nellie Newton pushes an object with twice the force for twice the distance, she does

Physics

1 answer:

Vanyuwa [196]3 years ago

8 0

ur answer would be 4x the work!!!

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Two objects of the same radius start from rest and roll without slipping down a ramp. The objects are a hollow cylinder and a so

Westkost [7]

Answer:

Solid cylinder

Explanation:

because hollow may blow and just bounce

8 0

3 years ago

The student quickly discovers that placing the marshmallow over the flame is more effective than heating the marshmallow on the

ANEK [815]

Answer:

The answer is convection.

Explanation:

There are three types of heat transfer: conduction, convection and radiation.

Conduction occurs when two objects touch each other and transfer heat.

Convection occurs when an object heats its surrounding fluid (like air, or water) and, since the hot fluids are less dense than the cold ones, they go up. So convection is a type of heat transfer that usually goes from down to up.

Radiation occurs when objects emanate heat in the form of electromagnetic waves that propagates in all directions.

So in this case, when the marshmallow is above the fire, it is exposed to convection, which does not occur when it is on the side of the fire.

4 0

4 years ago

A crate with a mass of m = 450 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate a

Zielflug [23.3K]

Answer: $F_{v} =\mu_{k} mg$

Magnitude of the force is 2601.9 N

Explanation:

m = 450 kg

coefficient of static friction μs = 0.73

coefficient of kinetic friction is μk = 0.59

The force required to start crate moving is $F_{s} =\mu_{s} mg$ .

but once crate starts moving the force of friction is reduced $F_{v} =\mu_{k} mg$ .

Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie $F_{v} =\mu_{k} mg$ .

Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.

Magnitude of the force

$F_{v} =\mu_{k} mg\\F_{v} =0.59 \times 450 \times 9.8\\F_{v} =2601.9 N$

4 0

4 years ago

The process of evaluating evidence to form an attitude is called

tatyana61 [14]

The process of evaluating evidence to form an attitude should be called Cognitive evaluation.

5 0

3 years ago

If a rock climber accidentally drops a 77.5-g piton from a height of 215 meters, what would its speed be just before striking th

Viktor [21]

Let us list out what we know from the question.

Initial Velocity $V_{i} = 0$ since the piton is 'dropped'.

Vertical Displacement of the piton D = 215 m

Acceleration due to gravity $a = 9.8 m/s^{2}$

Final Velocity $V_{f} = ?$

Using the equation, $V^{2} _{f} = V^{2} _{i} + 2aD$ and plugging in the known values, we get

$V^{2} _{f} = 0^{2} + 2(9.8)(215)$

Simplifying by taking square-root on both sides gives us $V_{f} = 64.915 m/s$

Thus, the speed of the piton just before striking the ground is 65 m/s.

4 0

3 years ago