Answer:
In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.
Answer:
0.67m/s²
Explanation:
Given parameters:
Mass of toy = 1.2kg
Force applied = 0.8N
Unknown:
Acceleration = ?
Solution:
According to newton's second law of motion;
Force = mass x acceleration
Now,
Acceleration =
Acceleration =
= 0.67m/s²
Answer:
Velocity of both masses after the collisio
Explanation:
Hope it will help
<h2>
<em><u>Brainlists please</u></em></h2>
Answer:
Final speed of the train is 7.5 m/s
Explanation:
It is given that,
Uniform acceleration of the train is, a = 1.5 m/s²
It starts from rest and travels for 5.0 s. We have to find the final velocity of the train. By using first equation of motion as :

Here, train starts from rest so, u = 0
v = 7.5 m/s
So, the final velocity of the train is 7.5 m/s. Hence, this is the required solution.