A rough surface for infrared waves may be polished for

A cyclist maintains a constant velocity of 4.1 m/s headed away from point A. At some initial time, the cyclist is 244 m from poi

astra-53 [7]

Answer:

$d=490\ m$ is his final displacement from the point A after 60 seconds.

Explanation:

Given:

Cyclist is moving away from A.

velocity of cyclist, $v=4.1\ m.s^{-1}$

displacement of the cyclist from point A at the time of observation, $d_i=244\ m$

time after which the next observation is to be recorded, $t=60\ s$

Now as the cyclist is moving away from point A his change in displacement after the mentioned time:

$\Delta d=v.t$

$\Delta d = 4.1 \times 60$

$\Delta d=246\ m$

<u>Now the the final displacement from point A after the mentioned time:</u>

$d=d_i+\Delta d$

$d=244+246$

$d=490\ m$

6 0

2 years ago

Car A has a mass of 1,200 kg and is traveling at a rate of 22km/hr. It collides with car B has a mass of 1,900 kg and is traveli

Zina [86]

<span>The momentum before the collision is equal to the momentum after the collision</span>

7 0

3 years ago

In general, as the energy of a sound wave increases, A. the sound gets softer and then louder. B. the sound gets louder. C. the

Vadim26 [7]

The sound gets louder, like hitting a metal pole on a thin metal beam, the energy increases as the sound does.

5 0

3 years ago

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What would be your estimate of the age of the universe if you measured a value for Hubble's constant of H0 = 30 km/s/Mly ? You c

Maksim231197 [3]

Answer:

The age of the universe would be 9.9 billion years

Explanation:

We can calculate an estimate for the age of the Universe from Hubble's Law. Let's suppose the distance between two galaxies is D and the apparent velocity with which they are separating from each other is v. At some point, the galaxies were touching, and we can consider that time the moment of the Big Bang.

Thus, the time it has taken for the galaxies to reach their current separations is:

$\displaystyle{t=D/v}$