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olchik [2.2K]
4 years ago
15

A horse running at 3 m/s speeds up with a constant acceleration of 5 m/s2. How fast is the

Physics
1 answer:
Elan Coil [88]4 years ago
7 0

Answer:

The horse is going at 12.72 m/s speed.

Explanation:

The initial speed of the horse (u) = 3 m/s

The acceleration of the horse (a)= 5 m/s^{2}

The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m

Applying the second equation of motion to find out the time,

s=ut+\frac{1}{2}at^{2}

15.3=3t+2.5t^{2}

2.5t^{2}+3t-15.3=0

Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.

Now applying first equation of motion, to find out the final velocity,

v=u+at

v=3+1.945*5

v=3+9.72

v=12.72 m/s

The horse travels at a speed of 12.72 m/s after covering the given distance.

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Answer:

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\Delta GPE = mg\Delta h

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Read 2 more answers
Two forces F1 and F2 are applied at the same point of an object. F1 has a magnitude of 20 N and is directed at an angle of 120 d
butalik [34]

Answer:

The value is  \vec F_{n} =   -5.67 i +14.82 j  \ \  N

Explanation:

From the question we are told that

   The magnitude of the first force is  F_1 =  20 \  N

    The angle which it makes with the x-axis is  \theta_1 =  120 ^o

    The magnitude of the second force is  F_2 =  5 \  N

     The angle which it make with x-axis is  \theta_2 =   -30 ^o

Generally the x-component of the first force is  

       F__{1x}} =  20 cos (120 )'

=>     F__{1x}} =  -10 \  N

Generally the y-component of the first force is  

       F__{1y}} =  20 sin (120 )

=>     F__{1y}} =  17.32  \  N

Generally the vector representation of the first force is mathematically represented as

       \vec F_1 = [ -10 i  +  17.32 j \ ] \ N

Generally the x-component of the second force is  

       F__{2x}} =  20 cos (-30 )

=>     F__{2x}} =  4.33 \  N

Generally the y-component of the second force is  

       F__{2y}} =  20 sin (-30 )

=>     F__{2y}} =  -2.5  \  N

Generally the vector representation of the first force is mathematically represented as

       \vec F_2 = [ 4.33 i  - 2.5 j \ ] \ N

Generally the net force acting that point is mathematically represented as

       \vec F_{n} =   -10 i  +  17.32 j   + 4.33 i  - 2.5 j

=>    \vec F_{n} =   -5.67 i +14.82 j  \ \  N

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The oxygen is the Solute, since this is smaller in quantity.

The Nitrogen is the Solvent, since this is more in quantity.

The air is the Solution, this is the mixture itself.
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