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Helen [10]
3 years ago
10

The perimeter of a rectangular garden is 120 meters. the length is 6 meters longer than twice the width. find the dimensions of

the garden.
Mathematics
1 answer:
Allushta [10]3 years ago
5 0
20 the answer is 20 bhoop
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Simplify the given equation.
Ede4ka [16]

Answer:

Part 1) 4-7x=15

The value of x is -\frac{11}{7}

Part 2) x=27

Step-by-step explanation:

Part 1)  Simplify the given equation

we have

6 - (3x + 10)+4(2 - x)=15

In the left side, remove the parenthesis and apply the distributive property

Remember that

(-1)(+1)=-1\\(-1)(-1)=+1

so

6 -3x-10+4(2)-4(x)=15

6 -3x-10+8-4x=15

Combine like terms left side

4-7x=15

Adds 7x both sides

4=15+7x

subtract 15 both sides

-11=7x

Divide by 7 both sides

x=-\frac{11}{7}

Part 2) Solve for x.

5(x + 1) = 4(x + 8)

Apply distributive property both sides

5x+5=4x+32

Group terms that contain the same variable

5x-4x=32-5

Combine like terms

x=27

6 0
3 years ago
PLEASE HELP ME THIS IS DUE IN TWO HOURS! :(
Damm [24]

Answer:

2.0 x 10^{1}

Step-by-step explanation:

1. length = 3.2 x 10^{5} m

width = 1.6 x 10^{4} m

Area of a rectangle = length x width

                                = (3.2 x 10^{5}) x (1.6 x 10^{4})

                                = 5.12 x 10^{9} m^{2}

2. length = 1.28 x 10^{7} m

   width = 8 x 10^{3} m

Area of a rectangle = length x width

                                 = (1.28 x 10^{7}) x (8 x 10^{3})

                                 = 1.024 x 10^{11} m^{2}

\frac{Area of rectangle 2}{Area of rectangle 1} = \frac{1.024*10^{11} }{5.12*10^{9} }

                       = 20

                       = 2.0 x 10^{1}

Thus,

The area of rectangle 2 is 2.0 x 10^{1} times greater than the area of rectangle 1.

5 0
3 years ago
Several people were polled regarding their favorite type of dessert. They were asked to choose one of the following: ice cream,
zavuch27 [327]
40 x .35 = 14 people
7 0
3 years ago
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Can somebody explain this in a basic way and help me graph it??!!
7nadin3 [17]

Hello!

To graph this, you will want to create two points based off of the equation. You plug an x-value into the equation, and you put the y-value outcome with it as an ordered pair. You do this twice, giving you two points to connect.

For example, let's plug in an x-value 1, giving us (1,y)

y= 1-3 (We remove the absolute value)

y=-2 (Subtract)

This gives us one point, (1,-2)

Let's try using -2 as another point.

y= 2-3 (Remove absolute value)

y= -1 (Subtract)

This gives us the point (-2,-1)

To graph, you would draw a straight line through the points (1,-2) and (-2,-1). Note you could do this with any x-value and you would get the same line.

I hope this helps!


3 0
3 years ago
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3 less than the quotient of a number y and 4<br><br><br> Answer?
Vesna [10]
Y/4-3 if you needed to make it into an equation that would be it 
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4 years ago
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