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romanna [79]
3 years ago
9

If you eat 3.00 moles of sugar, how many molecules did you consume?

Chemistry
1 answer:
Anna71 [15]3 years ago
3 0
1 mole is 6.02x 10^23 molecules

3 * 6.02*10^23 =1.806*10^24 molecules

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What is the atomic number and name of an element that has 15 protons in its nucleus?
just olya [345]

Answer:

phosphorus.

Explanation:

The atomic number of phosphorus is 15 so the protons will be 15.

4 0
3 years ago
Read 2 more answers
The electron configuration of an element is 1s22s22p4. Describe what most likely happens when two atoms of this element move tow
Vlad1618 [11]

Answer:

When the two atoms move towards each other a compound is formed by sharing electron pairs supplied by each of the atoms to enable them have the stable 8 (octet) valency electrons in their outermost shell

Explanation:

The electronic configuration of the given element can be written as follows;

1s²2s²2p⁴

The given electronic configuration is equivalent to that of oxygen, therefore, we have;

The number of electrons in the valence shell = 2 + 4 = 6 electrons

Therefore, each atom requires 2 electrons to complete its 8 (octet) electrons in the outermost shell

When the two atoms move towards each other, they react and combine to form a compound by sharing 4 electrons, 2 from each atom, such that each atom can have an extra 2 electrons in its outermost orbit in the newly formed compound and the stable octet configuration is attained by each of the atoms in the newly formed compound.

4 0
3 years ago
Read 2 more answers
given that 32.0g sulphur contains 6.02×10^23 sulphur atoms,how many atoms are there in 2.70g of aluminum​
dangina [55]

Answer:

6.022 × 10²² atoms

Explanation:

Generally 1 mol of any element contains 6.02×10^23  atoms. The number 6.022 × 10²³ is known as Avogadro's number.

Mass of Aluminium = 2.70g

Molar mass = 27g/mol

Number of moles = Mass / Molar mass = 2.70 / 27 = 0.1 mol

1 mol =  6.022 × 10²³

0.1 mol = x

x = 6.022 × 10²³ * 0.1 = 6.022 × 10²² atoms

5 0
3 years ago
Manganese(iv) oxide reacts with aluminum to form elemental manganese and aluminum oxide: 3mno2+4al→3mn+2al2o3part awhat mass of
Oxana [17]
<span>12.4 g First, calculate the molar masses by looking up the atomic weights of all involved elements. Atomic weight manganese = 54.938044 Atomic weight oxygen = 15.999 Atomic weight aluminium = 26.981539 Molar mass MnO2 = 54.938044 + 2 * 15.999 = 86.936044 g/mol Now determine the number of moles of MnO2 we have 30.0 g / 86.936044 g/mol = 0.345081265 mol Looking at the balanced equation 3MnO2+4Al→3Mn+2Al2O3 it's obvious that for every 3 moles of MnO2, it takes 4 moles of Al. So 0.345081265 mol / 3 * 4 = 0.460108353 mol So we need 0.460108353 moles of Al to perform the reaction. Now multiply by the atomic weight of aluminum. 0.460108353 mol * 26.981539 g/mol = 12.41443146 g Finally, round to 3 significant figures, giving 12.4 g</span>
7 0
4 years ago
A student uses a balance to determine the mass of an object as 5.719 grams. the correct mass of the object is 5.586 grams. what
zaharov [31]
The percentage error is given by multiplying relative error by 100%.
Therefore, to get the percentage error we need relative error which is given by dividing the absolute error with the actual value. 
Absolute error = 0.133
Percentage error = 0.133/5.586 × 100%
                            = 2.38%
The percentage error is therefore; 2.38%
8 0
3 years ago
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