All categories

4 years ago

Which remains the same as the distance of an object from Earth changes?

Chemistry

1 answer:

zvonat [6]4 years ago

3 0

Answer:

its mass which is C

Explanation:

You might be interested in

What is the percent by mass of nahco3 in a solution containing 10 g of nahco3 dissolved in 400 ml of h2o?

Marat540 [252]

Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %

7 0

3 years ago

a student design and experiment to test how the speed of a 90kg bumper car impacts the strength of the collision of that bumper

Ksenya-84 [330]

Answer:

a student design and experiment to test

4 0

3 years ago

How many molecules are in 13.2 g NO2?

DochEvi [55]

Answer:

No. of molecules= mass/molar mass ×avogadro no.

= 13.2/50×6.02×10°23

No. of molecules =1.59×10°23

Explanation:

5 0

3 years ago

How do you write a polynomial in standard form?

olchik [2.2K]

<span>One way to write a polynomial is in standard form. In order to write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write. First, look at the degrees for each term in the expression.</span> and in this way you will be able to write polynominal in standard form.

8 0

3 years ago

2p is the correct representation for the sub-shell with n = 2 and l = 1.

boyakko [2]

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

s = 1 orbital

p = 3 orbitals

d = 5 orbitals

f = 7 orbitals

For n = 4

l = 0 to (n-1) = 0 to 3 = (4s , 4p , 4d , 4f)

Number of subshells = 4

Number of orbitals = 1 + 3 + 5 + 7 = 16

The maximum number of electrons the n = 4 shell can contain:

Each orbital can holds upto two electrons, then 16 orbitals will have :

$16\times 2=32$

32 is the maximum number of electrons the n = 4 shell can contain

6 0

4 years ago

Read 2 more answers