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Ludmilka [50]
3 years ago
15

Can you explain to me how exponents work?

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0

You can't combine exponents when the bases aren't the same.

x^{2}   "x" is where the base is

For example:

(x^{2} )(y^4)=x^2y^4     (the bases are x and y)

\frac{x^3}{y^7} =\frac{x^3}{y^7}


When an exponent is multiplied directly to another exponent, you multiply the exponents together.

For example:

(x^{2} )^4=x^{2(4)}=x^8

(x^3)^5=x^{3(5)}=x^{15}

(2x^{2})^2  You can look at it like this:  

(2^1x^{2} )^2=2^{1(2)}x^{2(2)} = 2^2x^4=4x^4


When a variable with an exponent is multiplied by a variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3} )=x^{2+3}=x^5

(x^3)(x^4)=x^{3+4}=x^7

(2x)(x^2)=2x^{1+2}=2x^3


When an exponent is divided by an exponent, you subtract the exponents.

For example:

\frac{x^5}{x^3} =x^{5-3}=x^2

\frac{y^4}{y^1}=y^{4-1}=y^3


When an exponent is negative, you move the number and its exponent to the other side of the fraction to make the exponent positive.

For example:

x^{-3} or \frac{x^{-3}}{1}=\frac{1}{x^3}

x^{-2}=\frac{1}{x^2}

\frac{1}{y^{-5}}=\frac{y^5}{1} or y^{5}


LuckyWell [14K]3 years ago
4 0

Answer:

1^2 is one squared which means

1x1

1^3 is

1x1x1

2^4 is

2x2x2x2 which equals 16

Step-by-step explanation:


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raketka [301]
         In standard form,it should be     0 +0.9 +0.05 
4 0
2 years ago
there are 800 seats in the varsity theater. during regular preformances, all seats cost $12 each. It costs the owner $275 to pay
r-ruslan [8.4K]

Answer:

The correct answers are the following:

A) <u>P=12n-275 </u>

B) <u>124 </u>

C) <u>Decrease by $100 </u>

Step-by-step explanation:

A) <u>P=12n-275 </u> - Each person (n) pays $12, then the cost/expense ($275) is subtracted from the income to get the profit.

B) <u>1,213=12n-275</u>  - Plug in the value for P ($1,213).

1,488=12n  - Add $275 to both sides.

124=n  - Divide both sides by $12.

<u>n=124 </u> - This the number (n) of people that attended.

C) <u>P=12n-375 </u> - Change the value for expense to $375.

P=12(124)-375  - Plug in the value for n (124).

P=1488-375  - Simplify and find the difference.

<u>P=1,113 </u> - This is your profit.

<u>1,113-1,213=-100 </u> - $100 reduction/decrease of profit (or -$100 to profit)

Hope this helps!

6 0
2 years ago
The drama club was selecting which carnival booths to sponsor at the fall carnival from a list of nine. How many different ways
denis-greek [22]

Answer:

Option B

Step-by-step explanation:

Here we have to apply " combination and permutation. " It is given that the drama club had to choose three booths from a selection of 9, considering the possible ways to choose so. This is a perfect example of combination. In nCr, n corresponds to 9, respectively r corresponds to 3.

\mathrm{n\:choose\:r},\\nCr=\frac{n!}{r!\left(n-r\right)!},\\\\\frac{9!}{3!\left(9-3\right)!} =\\\frac{9!}{3!\cdot \:6!} =\\\\\frac{9\cdot \:8\cdot \:7}{3!} =\\\frac{504}{6} =\\\\84\\\\Solution = Option B

Hope that helps!

8 0
3 years ago
Oh mah lord please please help me
Alenkinab [10]

Option 2: 4^{\frac{1}{6}} is the correct answer.

Step-by-step explanation:

The radical expressions like these are simplified by using fractional exponents

given

\frac{\sqrt{4}}{\sqrt[3]{4} }

Converting radicals into exponents

When there is no base the exponent is 1/2 and as the base is 3, the exponent will be 1/3

So

=\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}

As the bases of numerator and denominator is same, the exponents can be subtracted

=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}

Hence,

Option 2: 4^{\frac{1}{6}} is the correct answer.

Keywords: Exponents, radicals

Learn more about radicals at:

  • brainly.com/question/6073431
  • brainly.com/question/6075514

#LearnwithBrainly

7 0
3 years ago
WILL GIVE BRAINLIEST
jok3333 [9.3K]

Answer:

J'(-2,5)

K'(-7,5)

M'(-3.5,2)

L'(5.5,2)

Step-by-step explanation:

Please refer to the image attached to this answer.

Trapezoid JKLM is reflected over the x-axis, what do we notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis is described below.

Point J , K L and M  , when reflected over x axis , there distance from the y axis remains the same in second quadrant. the x coordinate becomes negative however  the y coordinates remains the same.

The coordinates will be as shown in the image attached.

3 0
3 years ago
Read 2 more answers
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