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kirza4 [7]
3 years ago
7

Students in a physical education class practiced rope climbing. Students gripped a rope that hung from the ceiling and lifted th

emselves up the rope using only their arms. What must be measured to determine the power output of the climbers?
A) tension on the rope and the final height
B) body mass, final height, and the tension on the rope
C) tension on the rope and the time required to complete the climb
D) body mass, final height, and the time required to complete the climb
Physics
2 answers:
Lelechka [254]3 years ago
6 0
Body mass final height and the tension on the rope
ahrayia [7]3 years ago
5 0

Answer:

D) body mass, final height, and the time required to complete the climb

Explanation:

Power is defined as the rate at which a work is done

So there power out put could be measured using the mass of the climber hieght reached with time

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A racecar driver is driving her car down the drag strip at 120 m/s. What is the shortest distance in which she can brake and sto
DaniilM [7]

Answer:

1034.78 m

Explanation:

The shortest distance is the displacement of the car from initial position to final position.

Displacement of body is given using Newton's equations of motion.

Given:

Initial velocity, u = 120 m/s

Final velocity, v = 0 m/s( As the car stops in its final position)

Coefficient of static friction, \mu=0.71

Acceleration due to gravity, g=9.8\textrm{ } m/s^{2}

Now, when brakes are applied, only friction acts on the body in a direction opposite to that of its motion.

The acceleration of the car when friction acts the stopping force is given as:

a=- \mu g.

The acceleration is negative as it reduces the velocity of the motion and acts in the direction opposite to that of the motion.

Plug in 0.71 for \mu and 9.8 m/s² for g. Solve for a.

So, a=-0.71\times 9.8=-6.958\textrm{ }m/s^{2}.

Now, displacement of the car is given using the following equation of motion:

v^{2}=u^{2} +2aS

Here, S is the displacement of the racing car.

Plug in 120 m/s for u, 0 m/s for v, -6.958 m/s² for a. Solve for S. This gives,

0^{2} =(120)^{2}+2(-6.958)S\\13.916S=14400\\S=\frac{14400}{13.916}=1034.78\textrm{ m}

Therefore, the shortest distance in which she can brake and stop is 1034.78 m.

5 0
4 years ago
Read 2 more answers
9 The diagram shows a uniform beam PQ. The length of the beam is 3.0 m and its weight is 50 N. The beam is supported on a pivot
tankabanditka [31]

equilibrium = 1/1

50 N/x = 1/1

x = 1/1 × 50 N

x = 50 N (B)

#LearnWithEXO

6 0
3 years ago
A 21 kg chair initially at rest on a horizontal floor requires a 175 N horizontal force to set it in motion. Once the chair is i
Alika [10]

Answer:\mu =0.85

Explanation:

Given

mass of chair m=21 kg

Force required to set chair in motion is 175 N

Once the chair is in motion 137 N is require to move it with constant velocity

i.e. 175 N is the amount of force needed to just overcome static friction and 137 is the kinetic friction force

thus

f_s(static\ friction)=\mu \cdot N

where \muis the coefficient of static friction and N is Normal reaction

N=mg

f_s=\mu mg

\mu mg=175

\mu =\frac{175}{21\times 9.8}

\mu =0.85

8 0
3 years ago
A 2-kg object is moving at 3 m/s. A 4-N force is applied in the direction of motion and if the object has a final velocity 7m/s.
aniked [119]
Intial velocity u=3m/s
final velocity v
2
=u
2
+2as=3
2
+(2×2×5)=29 ⟹v=5.3m/s

KE=
2
1
​
m(v
2
−u
2
)=
2
1
​
×2×((5.3)
2
−3
2
)=20J
7 0
3 years ago
In the compound MgCl2, how many atoms of Mg are there?
Aleksandr [31]
There is 1 Mg and 2 Cl i think
3 0
3 years ago
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