A 2-kg object is moving at 3 m/s. A 4-N force is applied in the direction of motion and if the object has a final velocity 7m/s.
calculate the distance that the object moves
1 answer:
Intial velocity u=3m/s
final velocity v
2
=u
2
+2as=3
2
+(2×2×5)=29 ⟹v=5.3m/s
KE=
2
1
m(v
2
−u
2
)=
2
1
×2×((5.3)
2
−3
2
)=20J
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