False, that does not apply to some
<span>F=ma = 3000x2m/sec^2 =6000 newtons. </span>
Answer:
Explanation:
Considering non - relativistic approach : ----
Speed of electron = 1 % of speed of light
= .01 x 3 x 10⁸ m /s
= 3 x 10⁶ m /s
Kinetic energy of electron = 1/2 m v²
= .5 x 9.1 x 10⁻³¹ x ( 3 x 10⁶ )²
= 40.95 x 10⁻¹⁹ J
Kinetic energy in electron comes from lose of electrical energy equal to
Ve where V is potential difference under which electron is accelerated and e is electronic charge .
V x e = kinetic energy of electron
V x 1.6 x 10⁻¹⁹ = 40.95 x 10⁻¹⁹
V = 25.6 Volt .
Answer:
everyone else does this to me so lol
Explanation:
Answer:
468 m
Explanation:
So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.
The length CE is length AE - length AC = 284 - 234 = 50 m
We can calculate the angle ECD:
![tan(\hat{ECD}) = \frac{ED}{EC} = \frac{100}{50} = 2](https://tex.z-dn.net/?f=tan%28%5Chat%7BECD%7D%29%20%3D%20%5Cfrac%7BED%7D%7BEC%7D%20%3D%20%5Cfrac%7B100%7D%7B50%7D%20%3D%202)
![\hat{ECD} = tan^{-1} 2 = 63.43^o](https://tex.z-dn.net/?f=%5Chat%7BECD%7D%20%3D%20tan%5E%7B-1%7D%202%20%3D%2063.43%5Eo)
This is also the angle ACB, so we can find the length AB:
![tan(\hat{ACB}) = \frac{AB}{AC} = \frac{AB}{234}](https://tex.z-dn.net/?f=tan%28%5Chat%7BACB%7D%29%20%3D%20%5Cfrac%7BAB%7D%7BAC%7D%20%3D%20%5Cfrac%7BAB%7D%7B234%7D)
![2 = \frac{AB}{234}](https://tex.z-dn.net/?f=2%20%3D%20%5Cfrac%7BAB%7D%7B234%7D)
![AB = 2*234 = 468 m](https://tex.z-dn.net/?f=AB%20%3D%202%2A234%20%3D%20468%20m)
So the height of the building is 468m