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qwelly [4]
2 years ago
7

Which describes the difference between the two sequences?

Mathematics
1 answer:
mash [69]2 years ago
8 0

Answer:

its a)the first sequence is geometric bc of the common ratio of 2. the second sequence is arithmetic bc of the common difference of 7.

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Please help on the half circle one
yan [13]

Answer:

28.26

Step-by-step explanation:

Area of a circle is pi * radius squared

The diameter is 6, so the radius is 3

pi * 3^2 = 3.14 * 9 = 28.26

5 0
2 years ago
Question in picture. Thanks!
KonstantinChe [14]
2x^2+4x+2
Carry the 2 over to the 3 behind the 4 and multiply so 2times2 is 4. So i new equation is.
X^2+4x+4
Now you have to find the factors of 4 which is 1,4 and 2,2
So now you have to see which one adds up to 4 so 1+4 is 5 so cross that out and 2+2=4.
So the two number is 2 and 2 now you have to bring down the x^2 and the signs.
(X+2) (X+2) and thats your answer
8 0
3 years ago
15 points!!<br> Look at the picture to see the problem. What do you think?
Anna007 [38]

Answer:

I don't remember well, and I'm not sure if this is correct, but, I think the answer is  This is beacuse ∠FCD are facing with ∠CDG meaning it would be a same side interior angle.

6 0
2 years ago
Read 2 more answers
What is 4/16 ÷ 3/4 ​
Kobotan [32]

Answer:

4/12 simplified to 1/3.

Step-by-step explanation:

4/16 x 4/3 = 4/12

4/12 = 1/3

5 0
2 years ago
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(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
2 years ago
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