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3 years ago

A number x is at most -3. What’s the inequality

Mathematics

2 answers:

Inessa05 [86]3 years ago

8 0

Answer: x<*-3

It wont let me write the less or equal sign*

Leto [7]3 years ago

7 0

Answer:

I believe it would be X ≤ -3

Step-by-step explanation:

My answer is stating x is -3 or less. this means it is including -3 as a possible answer.

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The area of a triangle is 20 cm², and the

grandymaker [24]

Answer:

Heavenly, we need the forumula for the area of a triangle, do you know it?

Step-by-step explanation:

Area of a triangle is (1/2 ) * B*H

where B = base

H = height

then

A = 1/2* B * H

A is given to be 20

B = b

H = b+4

plug all those into the formula,

20 = (1/2)*b*(b+4)

use your algebra skillz :P

20 = 1/2 *( $b^{2}$ + 4b)

20*2 = $b^{2}$ + 4b

40 = $b^{2}$ + 4b

0 = $b^{2}$ + 4b-40

rewrite the above so it's in x format

$x^{2}$ + 4x -40 = 0

use the quadratic formula to find x , and for our problem, remember that x represents the base, or b, but don't mix it up with the b in the quadatic fomula, with the b of the triangle, which is the base, they are differnt "b"s :P

X = (b± $\sqrt{b^{2}-4*a*c }$ ) / 2*a

a = 1

b = 4

c = -40

x = (4± $\sqrt{4^{2}-4*1*(-40) }$ ) /2*1

x = ( 4± $\sqrt{16+160}$ ) / 2

x = (4± $\sqrt{176}$ ) / 2

x = (4±13.266499)/2

x= 2±6.633249

x = 2 + 6.633249 = 8.633

b= 8.633 cm

5 0

2 years ago

(cot^2x - 1)/(csc^2x) = cos2x

Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

$cos(2x)=cos^2x-sin^2x$ ,

$cos(2x)=1-2sin^2x$ , and

$cos(2x)=2cos^2x-1$

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

$\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$