16000
is the answer
because I used the calculater
Answer : The partial pressure of helium is, 
Solution : Given,
Molar mass of
= 32 g/mole
Molar mass of helium = 4 g/mole
Molar mass of
= 28 g/mole
Total pressure of gas = 
As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.
First we have to calculate the moles of oxygen, helium and nitrogen gas.



Now we have to calculate the total number of moles of gas mixture.


Now we have to calculate the moles fraction of helium gas.

Now we have to calculate the partial pressure of helium.

where,
= partial pressure of helium
= total pressure
= mole fraction of helium
Now put all the given values in this formula, we get

Therefore, the partial pressure of helium is, 
d. Fe(s) and Al(s)
<h3>Further explanation</h3>
In the redox reaction, it is also known
Reducing agents are substances that experience oxidation
Oxidizing agents are substances that experience reduction
The metal activity series is expressed in voltaic series
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the metal located on the left can push the metal on the right in the redox reaction
The electrodes which are easier to reduce than hydrogen (H), have E cells = +
The electrodes which are easier to oxidize than hydrogen have a sign E cell = -
So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)
The metal : d. Fe(s) and Al(s)
Answer: I believe the answer would be methane
Explanation:
Hope this helps