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dimulka [17.4K]
3 years ago
12

Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Which shows the correct substitution of the

values a, b, and c into the quadratic formula?
Chemistry
1 answer:
bekas [8.4K]3 years ago
8 0
The correct values I believe would be a=1 b=-2 and c=-3.
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Trimix 10/50 is a gas mixture that contians 10% oxygen and 50% helium, and the rest is nitrogen. If a tank of trimix 10/50 has a
Marat540 [252]

Answer : The partial pressure of helium is, 1.815\times 10^4KPa

Solution : Given,

Molar mass of O_2 = 32 g/mole

Molar mass of helium = 4 g/mole

Molar mass of N_2 = 28 g/mole

Total pressure of gas = 2.07\times 10^4KPa

As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.

First we have to calculate the moles of oxygen, helium and nitrogen gas.

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{10g}{32g/mole}=0.3125moles

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{50g}{4g/mole}=12.5moles

\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{40g}{28g/mole}=1.428moles

Now we have to calculate the total number of moles of gas mixture.

\text{Total number of moles of gas}=\text{Moles of oxygen gas}+\text{Mole of helium gas}+\text{Moles of nitrogen gas}

\text{Total number of moles of gas}=0.3125+12.5+1.428=14.24moles

Now we have to calculate the moles fraction of helium gas.

\text{Mole fraction of He gas}=\frac{\text{Moles of He gas}}{\text{Total number of moles of gas}}=\frac{12.5}{14.25}=0.877

Now we have to calculate the partial pressure of helium.

p_{He}=X_{He}\times P_T

where,

p_{He} = partial pressure of helium

P_T = total pressure

X_{He} = mole fraction of helium

Now put all the given values in this formula, we get

p_{He}=(0.877)\times (2.07\times 10^4KPa)=1.815\times 10^4KPa

Therefore, the partial pressure of helium is, 1.815\times 10^4KPa

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<h3>Further explanation</h3>

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The metal  : d. Fe(s) and Al(s)

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