Answer:
molality FeCl3= 2.579 molal
molarity FeCl3 = 2.333 M
mol fraction FeCl3 = 0.0444
Explanation:
Step 1: Data given
Mass % = 29.5 %
Density = 1.283 g/mL
Molar mass FeCl3 = 162.2 g/mol
Step 2: Calculate mass solution
Suppose we have 1L = 1000 mL solution
Mass solution = 1.283 g/mL * 1000 mL = 1283 grams
Step 3: Calculate mass FeCl3
Mass FeCl3 = 0.295 * 1283 grams
Mass FeCl3 = 378.485 grams
Step 4: Calculate mass of water
Mass water = 1283 - 378.485 = 904.515 grams
Step 5: Calculate moles FeCl3
Moles FeCl3 = mass FeCl3 / molar mass FeCl3
Moles FeCl3 = 378.485 grams / 162.2 g/mol
Moles FeCl3 = 2.333 moles
Step 6: Calculate moles H2O
Moles H2O = 904.515 grams / 18.02 g/mol
Moles H2O = 50.195 moles
Step 7: Mol fraction FeCl3
Mol fraction FeCl3 = 2.333 / (50.195+2.333)
Mol fraction FeCl3 = 0.0444
Step 8: Calculate molality
Molality = moles FeCl3 / mass H2O
Molality = 2.333 moles / 0.904515 kg
Molality = 2.579 molal
Step 9: Calculate molarity
Molarity = moles / volume
Molarity FeCl3 = 2.333 moles / 1 L
Molarity FeCl3 = 2.333 M
