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Pie
3 years ago
15

______ have no definite shape, but definite volume

Chemistry
1 answer:
NemiM [27]3 years ago
3 0

Answer:

liquids

Explaination:

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During the drying cycle, clothes soaked in liquid PERC at 300 K at 1 atm are tumbled in a stream of warm air at 330 K at 1 atm t
djyliett [7]
The answer is option A
6 0
3 years ago
An experiment to measure the enthalpy change for the reaction of aqueous
Komok [63]

Given that, an experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter; the heat of the reaction in the whole system is calculated to be 2218.34 kJ

Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.

The formula used to calculate the heat of the reaction can be expressed as follows:

Q = mcΔT

where:

  • Q = quantity of heat transfer
  • m = mass
  • c = specific heat of water = 4.18 kJ/g °C (constant)
  • ΔT = change in temparature

From the information given:

  • The initial temperature (T₁) = 25° C
  • The final temperature (T₂) = 91.5° C

∴

The change in temperature i.e. ΔT = T₂ - T₁

ΔT = 91.5° C - 25° C

ΔT = 66.5° C

The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³

\mathbf{= (1 \times \dfrac{50}{1000})\ moles}

= 0.05 moles

  • Since the molar mass of CuSO₄ = 159.609 g/mol

Then;

Using the relation:

\mathbf{number \ of \ moles = \dfrac{mass}{molar \ mass}}}

By crossing multiplying;

mass of CuSO₄ = number of moles of CuSO₄ ×  molar mass of CuSO₄

mass of CuSO₄ = 0.05 moles  × 159.609 g/moles

mass of CuSO₄ = 7.9805 grams

∴

Using the formula from above:

Q = mcΔT

Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C

Q = 2218.34 kJ

Therefore, we can conclude that the heat of the reaction is 2218.34 kJ

Learn more about the chemical reaction here:

brainly.com/question/20250226?referrer=searchResults

8 0
3 years ago
Plz answer thx<br><br><br> ​How many moles are in 2.5 x 10^18 grams of water?
alex41 [277]

Answer:

1.39\times 10^{17} moles of water in 2.5\times 10^{18} g of water.

Explanation:

Mass of water = m = 2.5\times 10^{18} g

Molar mass of water = M = 18 g/mol

Moles = n = \frac{m}{M}

n=\frac{2.5\times 10^{18} g}{18 g/mol}=1.39\times 10^{17} moles

So, there are 1.39\times 10^{17} moles of water in 2.5\times 10^{18} g of water.

3 0
3 years ago
What is the electron configuration of an electrically neutral alkaline earth metal? please explain​
vlabodo [156]

Answer:

The elements in Group 2 (beryllium, magnesium, calcium, strontium, barium, and radium) are called the alkaline earth metals (see Figure below). These elements have two valence electrons, both of which reside in the outermost s sublevel. The general electron configuration of all alkaline earth metals is ns

8 0
3 years ago
Pizza is an example of a homogeneous mixture.
Kay [80]
No its a example of heterogeneous mixture
4 0
3 years ago
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