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lutik1710 [3]
4 years ago
8

Write the balanced molecular equation for the reaction of barium hydroxide with perchloric acid. What is the coefficient of H2O?

​
Chemistry
2 answers:
djyliett [7]4 years ago
7 0

Answer:

The reaction of perchloric acid and barium hydroxide yields to barium perchlorate (Ba(ClO4)2) and water (H2O). The resulting balanced equation is 2 HClO4 + Ba(OH)2 = Ba(ClO4)2 +2 H2O. This means, for every mole of barium perchlorate produced, 2 moles of perchloric acid and barium hydroxide are required.

Explanation:

MAVERICK [17]4 years ago
4 0

Answer:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

The coefficient of H2O is 2

Explanation:

Ba(OH)2 + HClO4 —> Ba(ClO4)2 + H2O

Now let us balance the equation as shown below:

There are 2 atoms of Cl on the right and 1 atom on the left. It can be balanced by putting 2 in front of HClO4 as shown below:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + H2O

Now, there are a total of 4 atoms of H on the left and 2 on the right. It is balanced by putting 2 in front of H2O as shown below

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

Now, the equation is balanced. From the balanced equation, the coefficient of H2O is 2

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1.65g of zinc is used to make 8g of zinc iodide. How much iodine is required for this reaction?
creativ13 [48]

Answer:

6.45 g of iodine, I₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + I₂ —> ZnI₂

Next, we shall determine the mass of Zn and I₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Zn = 65 g/mol

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SUMMARY:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Finally, we shall determine the mass of f I₂ needed to react with 1.65 g of Zn. This can be obtained as follow:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

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4 0
3 years ago
According to the electron-cloud model of the atom, an orbital is a
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Answer : Option 4) Region of the most probable electron location.


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7 0
4 years ago
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According to the second order formula:
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3 years ago
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