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lutik1710 [3]
4 years ago
8

Write the balanced molecular equation for the reaction of barium hydroxide with perchloric acid. What is the coefficient of H2O?

​
Chemistry
2 answers:
djyliett [7]4 years ago
7 0

Answer:

The reaction of perchloric acid and barium hydroxide yields to barium perchlorate (Ba(ClO4)2) and water (H2O). The resulting balanced equation is 2 HClO4 + Ba(OH)2 = Ba(ClO4)2 +2 H2O. This means, for every mole of barium perchlorate produced, 2 moles of perchloric acid and barium hydroxide are required.

Explanation:

MAVERICK [17]4 years ago
4 0

Answer:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

The coefficient of H2O is 2

Explanation:

Ba(OH)2 + HClO4 —> Ba(ClO4)2 + H2O

Now let us balance the equation as shown below:

There are 2 atoms of Cl on the right and 1 atom on the left. It can be balanced by putting 2 in front of HClO4 as shown below:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + H2O

Now, there are a total of 4 atoms of H on the left and 2 on the right. It is balanced by putting 2 in front of H2O as shown below

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

Now, the equation is balanced. From the balanced equation, the coefficient of H2O is 2

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Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. Suppose 2.1 grams of ethane i
swat32

Answer:

= 3.78 g H₂O

Explanation:

2C₂H₆ + 3O₂ => 4CO₂ + 6H₂O

2.1g C₂H₆ = 2.1g/30.0 g/mol = 0.07 mole ethane

3.68g O₂ = 3.68g/32 g/mol = 0.115 mole oxygen

Limiting Reactant:

A quick way to determine limiting reactant is to divide moles of reactant by its respective coefficient in the balanced molecular equation. The smaller value is the limiting reactant.

moles ethane = 0.07 mole / 2 (the coefficient in balanced equation) = 0.035

moles oxygen = 0.115 mole / 3 (the coefficient in balanced equation) = 0.038

Since the smaller value is associated with ethane, then ethane is the limiting reactant and the problem is worked from the 0.07 moles of ethane in an excess of O₂.

From the equation stoichiometry ...

2 moles C₂H₆  in an excess of O₂ => 6 moles H₂O

then 0.07 mole C₂H₆  in an excess of O₂ => 6/2(0.07 moles H₂O = 0.21 mole

Converting to grams of water produced

= 0.21 mole H₂O X 18 g/mol = 3.78 g H₂O

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4 years ago
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Why not D: Paired bond isn't a common phrase in chemistry.

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