The second one on the top right
Consider the attached figure. If AB has length 1, then BC has length sin(15°) and CD (the altitude of triangle ABC) has length sin(15°)·cos(15°).
By the double angle formula for sin(α), ...
... sin(2α) = 2sin(α)cos(α)
Rearranging, this gives
... sin(α)·cos(α) = sin(2α)/2
We have
... CD = sin(15°)·cos(15°) = sin(2·15°)/2
... CD = sin(30°)/2 = (1/2)/2 = 1/4
That is, the altitude, CD, is 1/4 the hypotenuse, AB, of triangle ABC.
Answer:
15 units
Step-by-step explanation:
ΔABC is right with ∠C = 90° and AB the hypotenuse
using Pythagoras' identity on the triangle
AB² = AC² + BC² , hence
BC² = AB² - AC² = 17² - 8² = 289 - 64 = 225
⇒BC = = 15 units
Answer:
<h2><em><u>ᎪꪀsωꫀᏒ</u></em></h2>
➪34/5
Step-by-step explanation:
6 4/5
u have to multiple 5by 6 and then add 4 in that
u will get the answer 34/5
Answer:
8
Step-by-step explanation:
The rule is multpily by 2 so 4*2=8.