Ask question

Ask question

All categories

Anuta_ua [19.1K]

3 years ago

15

PLS HELP I WILL GIVE YOU Brainliest

1 answer:

Sindrei [870]3 years ago

5 0

Answer:

3/2

Step-by-step explanation:

Because the problem tells you that the two triangles are similar, the value of a/b would be equivalent for both triangles. The fact that they are right triangles also indicates which sides are which in case the image was not drawn to scale. A is proportional to 2.1 and b is proportional to 1.4. So a/b= 2.1/1.4. This can reduce itself to 3/2 because both are divisible by .7

You might be interested in

Find the value of x.<br> A.5.2<br> B.5.8<br> C.13.2<br> D.37.4

aalyn [17]

Answer:

x=(14)(sin22)

x=5.24...

x=5.2

The answer is A.

Step-by-step explanation:

3 0

2 years ago

What is the median of these numbers<br> 32, 16, 54, 60, 26, 32

Snezhnost [94]

They are the odd ones

8 0

2 years ago

Read 2 more answers

Solve the system of equations by substitution.<br> 5x + y =18<br> Y=4x

mixer [17]

Answer:

x =2 y= 8

Step-by-step explanation:

6 0

2 years ago

I need to know what the volume of the cone in cubic inches please

ivolga24 [154]

Answer:

V = 118 in³

Step-by-step explanation:

The volume of a cone of radius r and height h is V = (1/3)(π)(r^2)(h).

In this case, the volume is V = (1/3)π(3 in)^2·(6 in), or π(18 in³)

Using 3.14 as the approximate value of π, we get V = 118 in³

6 0

2 years ago

* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both

Nina [5.8K]

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective $n^{th}$ terms as following:

Sequence A. $3n - 2$

Sequence B. $10 - 2n$

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the $n^{th}$ terms of the respective sequences as equal and let us verify that.

$3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}$

When we talk about $n^{th}$ terms, $n$ here is a whole number not a fractional number.

But as per the statement as stated by Sally $n$ is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

7 0

2 years ago