Question

ABCD is a quadrilateral. AB=CD Angle ABC = angle BCD Prove that AC = BD

Answer 1

• Answer:

compare the triangles ΔABC and ΔBCD

∡ABC = ∡BCD (given)

AB = CD (given)

BC = BC (common)  } = > (SAS) ΔABC ≡ ΔBCD = > AC = BD