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Svetlanka [38]
3 years ago
12

ABCD is a quadrilateral. AB=CD Angle ABC = angle BCD Prove that AC = BD

Mathematics
1 answer:
maks197457 [2]3 years ago
5 0
  • Answer:

compare the triangles ΔABC and ΔBCD

∡ABC = ∡BCD (given)

AB = CD (given)

BC = BC (common)  } = > (SAS) ΔABC ≡ ΔBCD = > AC = BD

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kompoz [17]
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#11 just multiply the 2 numbers
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3 years ago
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A path starts and ends at diffrent verticles, and is allowed to repeat vertices and edges.
almond37 [142]

Answer:

Step-by-step explanation:

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17c-10=4 ............................
Katarina [22]

Answer:

1.214 or 1\frac{3}{14} or \frac{17}{14}

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Next, you will divide both sides by the 17.

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7 0
3 years ago
What is y=2x^2-12x+16 in vertex form
Natasha2012 [34]

Answer:

y = 2(x-3)^2 - 2

Step-by-step explanation:

y = 2x^2 - 12x + 16

y = 2(x^2 - 6x + 8)

y = 2(x^2 - 6x +8 +1 -1) you "complete the square" by bringing the last term (8) up to "half of the middle co-efficient squared". Middle co-efficient is -6, half is -3, squared is 9. To get from 8 to 9 you must add 1 (+1), but if you add 1 you must subtract 1 (-1) so that you don't change the overall value of inside the bracket


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3 0
3 years ago
What is the value of x
Lilit [14]

Answer:

4

Step-by-step explanation:

For the first triangle which is triangle <KJL

Hypotenuse= 8✓2

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Opposite = ?

Therefore we will use Sine formula

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For the second triangle which is triangle <JML

Hypotenuse= 4✓2

Opposite=X

Angle=45°

Therefore we will use Sine formula again

Sin45°=X/4✓2

X=4

3 0
3 years ago
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