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3 years ago

ABCD is a quadrilateral. AB=CD Angle ABC = angle BCD Prove that AC = BD

Mathematics

1 answer:

maks197457 [2]3 years ago

5 0

Answer:

compare the triangles ΔABC and ΔBCD

∡ABC = ∡BCD (given)

AB = CD (given)

BC = BC (common) } = > (SAS) ΔABC ≡ ΔBCD = > AC = BD

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2 years ago

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A) The person that has a greater probability of selecting a quadrilateral is Robert.

B) The person that has a greater probability of selecting a polygon is; Robert.

C) The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

<h3>How to Identify Polygons?</h3>

Sandy has; Square, Rhombus, Equilateral Triangle, Regular Hexagon

Robert has Scalene Triangle, Kite, Right Isosceles Triangle, Isosceles Trapezoid, Quadrilateral.

A) Sandy's probability of selecting a quadrilateral = 2/4 = 0.5

Robert's probability of selecting a quadrilateral = 3/5 = 0.6

The person that has a greater probability of selecting a quadrilateral is Robert

B) The person that has a greater probability of selecting a polygon is; Robert because he has more.

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The Probability of Robert selecting a polygon with at least 2 sides parallel is; 2/5 = 0.4

The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

Read more about Polygons at; brainly.com/question/5715879

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