ABCD is a quadrilateral. AB=CD Angle ABC = angle BCD Prove that AC = BD
1 answer:
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first polygon
ext. angle=180°-120°
=60°
n=360°/60°
n=6
second polygon
n=2(6)=12
ext. ang= 360°/n = 360°/12° = 30°
int. ang = 180°-30°= 150°
answer is C