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Ne4ueva [31]
3 years ago
15

- Gas central heating is used for 5 days, using 102 kWh of energy. If 1 kWh of gas costs 7p, calculate the cost of using the cen

tral heating -
Physics
1 answer:
melamori03 [73]3 years ago
6 0

Answer:

Explanation:

Given that,

Gas central heating was used for 5days

At a rate of 102kWh of energy

Then, 1 kWh = 7p

So,

The total time is 5days

t = 5days

1 day = 24hours

Then, t = 5days = 5 × 24 = 120hours

Given 102kWh, then, they consumers 102 kW in one hour, then, for the 120hours,

The total energy used is 102 × 24

Then, total energy = 2448 kWh

So, 1 kWh = 7p,

Then, 2448 kWh = 7 × 2448

2448 kWh = 17,136 p.

So, the cost of the using central heat is 17,136 p

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Finger [1]
The answer is either answer B or answer C! Hope that helps
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3 years ago
A hot air balloon travels 18 kilometers west and then travels 50 kilometers east. What is the current position of the hot air ba
Firlakuza [10]

Answer:

32 km east

Explanation:

In order to find the final position of the balloon, we need to calculate its total displacement.

We have:

- Displacement towards west: 18 km

- Displacement towards east: 50 km

The two vectors are on the same line: this means that we can simply add them together (taking into account the proper direction) to obtain the total displacement.

Taking east as positive direction and west as negative direction, we have:

d = 50 + (-18) = 50 - 18 = 32 km

And since it is positive, it means that the final position of the balloon is 32 km east from its initial position.

7 0
3 years ago
A skull believed to belong to an ancient human being has a carbon-14 decay rate of 5.4 disintegrations per minute per gram of ca
larisa86 [58]

Answer:

9.43*10^3 year

Explanation:

For this question, we ought to remember, or know that the half life of carbon 14 is 5730, and that would be vital in completing the calculation

To start with, we use the formula

t(half) = In 2/k,

if we make k the subject of formula, we have

k = in 2/t(half), now we substitute for the values

k = in 2 / 5730

k = 1.21*10^-4 yr^-1

In(A/A•) = -kt, on rearranging, we find out that

t = -1/k * In(A/A•)

The next step is to substitite the values for each into the equation, giving us

t = -1/1.21*10^-4 * In(5.4/15.3)

t = -1/1.21*10^-4 * -1.1041

t = 0.943*10^4 year

8 0
4 years ago
A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
ycow [4]

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

\omega = \frac{\Delta \theta}{\Delta t}                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

\omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

5 0
3 years ago
Two loudspeakers S1 and S2, 2.20 m apart, emit the same single-frequency tone in phase at the speakers. A listener L is located
seropon [69]

Answer:

the lowest possible frequency of the emitted tone is 404.79 Hz

Explanation:

   Given the data in the question;

S₁ ←  5.50 m → L

↑

2.20 m

↓

S₂

We know that, the condition for destructive interference is;

Δr = ( 2m + \frac{1}{2} ) × λ

where m = 0, 1, 2, 3 .......

Path difference between the two sound waves from the two speakers is;

Δr = √( 5.50² + 2.20² ) - 5.50

Δr = 5.92368 - 5.50

Δr = 0.42368 m

v = f × λ

f = ( 2m + \frac{1}{2})v / Δr

m = 0, 1, 2, 3, ....

Now, for the lowest possible frequency, let m be 0

so

f = ( 0 + \frac{1}{2})v / Δr

f = \frac{1}{2}(v) / Δr

we know that speed of sound in air v = 343 m/s

so we substitute

f = \frac{1}{2}(343) / 0.42368

f = 171.5 / 0.42368

f = 404.79 Hz

Therefore, the lowest possible frequency of the emitted tone is 404.79 Hz

5 0
3 years ago
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