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Scilla [17]
4 years ago
14

Two identical sine waves are superimposed on one another creating a beat pattern. How far out of phase are the two waves? The sp

eed of sound is 340 m/sec.
a.180

b.10

c.90

d.360
Physics
1 answer:
Irina18 [472]4 years ago
8 0

when two sine waves are superimposed on one another, a beat pattern is observed . this beat pattern consists of high intensity and low intensity in sequence alternately. we get the high intensity pattern when the two waves meet in phase and we get low intensity when the two waves are out of phase.  the intensity is lowest when the two wave are completely out of phase or 180 degree phase difference between the waves.

hence correct choice is a.180



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An object thrown vertically upward from the surface of a celestial body at a velocity of 36 ​m/s reaches a height of sequalsminu
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Answer:

v = -1.8t+36

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40 seconds

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Explanation:

s=-0.9t^2+36t

Differentiating with respect to time we get

\frac{ds}{dt}=-1.8t+36\\\Rightarrow v=-1.8t+36

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0=-1.8t+36\\\Rightarrow t=\frac{-36}{-1.8}\\\Rightarrow t=20\ s

b) The object will reach the highest point after 20 seconds

s=-0.9t^2+36t\\\Rightarrow s=-0.9\times 20^2+36\times 20\\\Rightarrow s=360\ m

c) Highest point the object will reach is 360 m

s=-0.9t^2+36t\\\Rightarrow 360=-0.9t^2+36t\\\Rightarrow -0.9t^2+36t-360=0\\\Rightarrow -9t^2+360t-3600=0

\frac{-360\pm \sqrt{0}}{2\left(-9\right)}\\\Rightarrow t=20\ s

d) Time taken to strike the ground would be 20+20 = 40 seconds

[tex]v=u+at\\\Rightarrow v=0+0.9\times 2\times 20\\\Rightarrow v=36\ m/s

Acceleration will be taken as positive because the object is going down. Hence, the sign changes. 2 is multiplied because the expression is given in the form of s=ut+\frac{1}{2}at^2

e) The velocity with which the object strikes the ground will be 36 m/s

f) The speed will increase when the object has gone up and for 20 seconds and falls down for 20 seconds. The object speed will increase when it is coming down from its highest height.

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Answer:

COMPLETE QUESTION

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