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Scilla [17]
3 years ago
14

Two identical sine waves are superimposed on one another creating a beat pattern. How far out of phase are the two waves? The sp

eed of sound is 340 m/sec.
a.180

b.10

c.90

d.360
Physics
1 answer:
Irina18 [472]3 years ago
8 0

when two sine waves are superimposed on one another, a beat pattern is observed . this beat pattern consists of high intensity and low intensity in sequence alternately. we get the high intensity pattern when the two waves meet in phase and we get low intensity when the two waves are out of phase.  the intensity is lowest when the two wave are completely out of phase or 180 degree phase difference between the waves.

hence correct choice is a.180



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Which best describes series​
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Answer:

a single closed path of electrical components including a voltage source

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2 years ago
Abdominal breathing is a condition in which only the inferior half of the lungs can be seen expanding and contracting with each
lilavasa [31]

Answer:

The correct answer is - Damage to the nerves that control the diaphragm.

Explanation:

Abdominal breathing is a condition in which inferior half of the lungs can be seen relaxing or contracting and expanding with the breath. This condition occurs due to the various conditions that lead to the respiratory.

It is cause due to the damage to nerves that control the diaphragm. The phrenic nerve is one of the nerve of diaphragm initiates in the neck and passes down.

Thus, the correct answer is - Damage to the nerves that control the diaphragm.

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7 0
3 years ago
А geostationary satellite moves in an orbit of radius 6300km. Calculate the speed with which it moves in the orbit [π=22÷7]​
azamat

Answer:

15.3 m/s

Explanation:

Radius of orbit= 6400+6300 = 12700 km

Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m

Now,

       Speed= Distance / Time

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4 0
2 years ago
Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.
alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

m_e is the mass of the electron

Solving for v, we find

v=\sqrt{k\frac{e^2}{m_e r}}

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

r=5.3\cdot 10^{-11}m

while the electron mass is

m_e = 9.11\cdot 10^{-31}kg

and the charge is

e=1.6\cdot 10^{-19} C

Substituting into the formula, we find

v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

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They can be described as small in quantity and very dangerously radioactive.

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