Answer: The lead is more dense :)
Explanation:
D = 318 meters
vi = 0 m/s
vf =????
a = 9.81
Formula
=======
vf^2 = vi^2 + 2*a*d
Substitute and solve.
================
vf^2 = 0^2 + 2 * 9.81 * 318
vf^2 = 6239.16
v = sqrt(6239.16)
v = 78.990 m/s I guess down is minus in your classroom.
Anyway pick -79 <<<<<=======
Answer:
0.88 mm
Explanation:
Given
Wavelength of the atoms, λ = 502 nm = 502*10^-9 m
Radius of the screen away from the double slit, r = 1 m
We know that Y(20) = 11.4*10^-3 m
d = (20 * R * λ) / Y(20)
d = (20 * 1 * 502*10^-9)/11.4*10^-3
d = 1*10^-5 / 11.4*10^-3
d = 0.88 mm
Therefore, the distance of separation between the two slits is 0.88 mm
The frictional force between two bodies depends mainly on three factors: (I) the adhesion between body surfaces
(ii) roughness of the surface
(iii) deformation of bodies.
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