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nlexa [21]
3 years ago
9

The numbers of pages in the books in a library follow a normal distribution. If the mean number of pages is 180 and the standard

deviation is 30 pages, what can you conclude?
Mathematics
1 answer:
Katena32 [7]3 years ago
8 0
16% have fewer pages
84% have more pages
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Determine whether the number is a solution of the given inequality.
myrzilka [38]
The answer to the question is B -2 the other 2 are not correct
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A map of Brasilia has a scale of 1 inch to 5 miles. If the city is 2 7/16 inches across on the map, what is the distance across
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The answer is c because that is what the website said with the exact same question , I hope you don't need to show your work but the correct answer is c
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Answer for this...increasing percentages
MaRussiya [10]

Answer:

Since it's increasing add 3.5% to 100%

= 103.5% of £16470.45

= 103.5/100 × 16470.45

= 17046.92

= £17046.92

Hope this helps.

7 0
3 years ago
What are the parts of an algebraic expression, and how do they relate to polynomial expressions?
Arlecino [84]

The parts of algebraic expressions related to polynomials are variables and coefficients.

<h3>What are the parts of algebraic expressions?</h3>

The parts of algebraic expressions are;

  • Variables which are letters that represent numbers
  • Coefficients are numbers that multiply the variables
  • Constant is a number that is not multiplied by any variable

Polynomials are algebraic expressions composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, and multiplication

Polynomials consists of variables and coefficients. The variables in polynomials are also called indeterminates. The coefficients also multiply this variables.

Thus, the parts of algebraic expressions related to polynomials are variables and coefficients.

Learn more about algebraic expressions here:

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3 0
2 years ago
The number of compact discs N purchased each year, in millions, can be
Aleonysh [2.5K]

Answer:

126.5 years

Step-by-step explanation:

N(t) = 384(1.13)^t

2,000,000,000 = 384(1.13)^t

(1.13)^t = 2,000,000,000/384

log [(1.13)^t) = log (2,000,000,000/384)

t × log 1.13 = log (2,000,000,000/384)

t = [log (2,000,000,000/384)]/(log 1.13)

t = 126.5

8 0
1 year ago
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