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3 years ago

Which material most likely gets the warmest when placed in the Sun?

Physics

2 answers:

weeeeeb [17]3 years ago

8 0

The answer is brown mulch.

I have typed out the reasons for you in the attached picture.

Hope this helps. - M

oksano4ka [1.4K]3 years ago

8 0

Answer:

The answer is Brown Mulch

Explanation:

Thus brown Mulch is darker than the other subsantaces it will warm up faster than the others. It also depends on the type of material . Here is a list in order of the most likely to warm up the fastest.

Brown mulch
Beige sand
Yellow pebbles
White cement

You might be interested in

How will you connect 3 cells each of value 2V to give a total of 3V * Two in parallel with one in series Two in series with one

emmainna [20.7K]

Answer:

two of them in series with one in parallel

Explanation:

When two or more batteries are connected in

(a) series: the total voltage produced is equal to the sum of the voltages on each of the batteries. For example, if two batteries A and B of 3V and 2V respectively are connected in series, then the total voltage produced is

3V + 2V = 5V

(b) parallel: the total voltage produced is equal to the voltage on any one of the batteries. As a mention, only batteries of the same voltage should be connected together in parallel. For example, if two batteries A and B each of 4V are connected together in parallel, then the total voltage produced is 4V.

If these batteries are not of the same voltage, then the one of larger voltage will charge the one of the lower voltage until they both have the same voltage. That means that their eventual voltage will be the average of their voltages. For example, if two batteries A and B of 3V and 2V respectively, are connected in parallel, their total voltage will be,

(3V + 2V) / 2 =2.5V

Now, from the question.

Since there are three cells each of value 2V.

=>If we connect two of them in series, the total voltage from those two cells will be 2V + 2V = 4V

=>If we then connect this series connection in parallel with the third cell, then we have a parallel combination of 4V and 2V. Since they have different voltages, then the total voltage will be the average of the two voltages. i.e

(4V + 2V) / 2 = 6 / 2 = 3V

Therefore, to have a total of 3V from three cells each of 2V, we need to connect two of them in series with one in parallel

5 0

3 years ago

john throws .4 kg ball with velocity of 18 m/s. Hits .2 kg bottle and bottle flies 25 m/s. How fast is ball traveling after hitt

UNO [17]

Answer:

5.5 m/s

Explanation:

Assuming the bottle is initially stationary, we can write the law of conservation of momentum as follows:

$p_i = p_f\\m_b u_b = m_b v_b + m_B v_B$

where

$m_b = 0.4 kg$ is the mass of the ball

$u_b = 18 m/s$ is the initial velocity of the ball

$m_B = 0.2 kg$ is the mass of the bottle

$v_B = 25 m/s$ is the final velocity of the bottle

$v_b$ is the final velocity of the ball

Solving for $v_b$ ,

$v_b = \frac{m_b u_b - m_B v_B}{m_b}=\frac{(0.4 kg)(18 m/s)-(0.2 kg)(25 m/s)}{0.4 kg}=5.5 m/s$

6 0

3 years ago

One way to cool a gas is to let it expand. When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.°C is allowed to expand t

hichkok12 [17]

Answer:

The final temperature is T2= 5.35°C

Explanation:

Apply the Gay-lussacs's law we have

$\frac{P1}{T1} = \frac{P2}{T2}$

P1, initial pressure= 5.00 x 10^6 Pa

T1, initiation temperature= 25.°C

P2, final pressure= 1.07 x 10^6 Pa

T2, final temperature= ?

$\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2} \\$

Cross multiplying and making T2 subject of formula we have

$T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35$

T2= 5.35°C

6 0

3 years ago

A 0.5 kg stone is raised from 1m to 2m height from the ground. what is the change in potential energy of the stone?

Usimov [2.4K]

Given: The mass of stone (m) = 0.5 kg

Raised from heights (h₁) = 1.0 m to (h₂) = 2.0 m

Acceleration due to gravity (g) = 9.8 m/s²

To find: The change in potential energy of the stone

Formula: The potential energy (P) = mgh

where, all alphabets are in their usual meanings.

Now, we shall calculate the change in potential energy of the stone

Δ P = P₂ - P₁ = mg (h₂ - h₁)

or, = 0.5 kg ×9.8 m/s² ×(2.0 m - 1.0 m)

or, = 4.9 J

Hence, the required change in the potential energy of the stone will be 4.9 J

4 0

4 years ago

A two-liter bottle is one-fourth full of water and three-quarters full of air. The air in the bottle has a gage pressure of 340

Fantom [35]

Answer:

The value is $P_G = 2.925 *10^{5} \ Pa$

Explanation:

From the question we are told that

The volume of the bottle is $v = 2 \ L = 2 * 10^{-3} \ m^3$

The gauge pressure of the air is $P_g = 340 \ kPa = 340 *10 ^{3} \ Pa$

Generally the volume of air before the bottle is turned upside down is

$V_a = \frac{3}{4} * V$

$V_a = \frac{3}{4} * 2 *10^{-3}$

$V_a = 0.0015 \ m^3 }$

Generally the volume air when the bottle is turned upside-down is

$V_u = \frac{5}{6} * 2 *10^{-3}$

$V_u = 0.00167 \ m^3$

From the the mathematical relation of adiabatic process we have that

$P_g * V_a^r = P_G * V_u^r$

Here r is a constant with a value r = 1.4

$340 *10 ^{3} * 0.0015^{1.4} = P_G * 0.00167^{1.4}$

$P_G = 2.925 *10^{5} \ Pa$

3 0

3 years ago