Question

One way to cool a gas is to let it expand. When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.°C is allowed to expand to 3 times its original
volume, its final pressure is 1.07 x 10^6 Pa. What is its final temperature:​

Answer 1

Answer:

The final temperature is T2= 5.35°C

Explanation:

Apply the Gay-lussacs's law we have

$\frac{P1}{T1} = \frac{P2}{T2}$

P1, initial pressure= 5.00 x 10^6 Pa

T1, initiation temperature= 25.°C

P2, final pressure= 1.07 x 10^6 Pa

T2, final temperature= ?

$\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2}$

Cross multiplying and making T2 subject of formula we have

$T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35$

T2= 5.35°C