Answer:
E=
Explanation:
We are given that
Charge on ring= Q
Radius of ring=a
We have to find the magnitude of electric filed on the axis at distance a from the ring's center.
We know that the electric field at distance x from the center of ring of radius R is given by

Substitute x=a and R=a
Then, we get




Where K=
Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=
Force = mass * acceleration = 1500kg * 8m/s²
At the point of maximum displacement (a), the elastic potential energy of the spring is maximum:

while the kinetic energy is zero, because at the maximum displacement the mass is stationary, so its velocity is zero:

And the total energy of the system is

Viceversa, when the mass reaches the equilibrium position, the elastic potential energy is zero because the displacement x is zero:

while the mass is moving at speed v, and therefore the kinetic energy is

And the total energy is

For the law of conservation of energy, the total energy must be conserved, therefore

. So we can write

that we can solve to find an expression for v:
Answer:
T=183.21K
Explanation:
We have to take into account that the system is a ideal gas. Hence, we have the expression

where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant.
Thus, it is necessary to calculate n and V
V is the volume of a sphere

V=8.86*10^{50}L
and for n

Hence, we have (1 Pa = 9.85*10^{-9}atm)

hope this helps!!