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3 years ago

Please help me lol Im not good at this stuff

Mathematics

2 answers:

natima [27]3 years ago

7 0

The answer is c if they move it 8 units on the x axis it’s gonna stay on the x axis but the image would be in a different plate then what it is now

Oxana [17]3 years ago

3 0

Answer:

Step-by-step explanation:

yes they will end up in the same location

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The box plot describes the height of flowers selected randomly from two gardens. Use the box plot to find the median of Garden Y

Korvikt [17]

Answer:

Garden y median =6, garden z median =3

3 0

3 years ago

R is inversely proportional to A

MArishka [77]

Answer:

The formula is connecting R and A

$R = k \frac{1}{A}$

The value of 'K' = 18.15

Step-by-step explanation:

Step(i):-

Given that R is inversely proportional to A

R ∝ 1 / A

$R = k \frac{1}{A}$

Given R = 12 .1 and A = 1.5

$R = k \frac{1}{A}$

$12.1 = K (\frac{1}{1.5} )$

K = 12.1 × 1.5

K = 18.15

The value of 'K' = 18.15

5 0

3 years ago

Evaluate the expression is x = 2 and y = 4. 4x + 4y

Zanzabum

8+16

If you want the answer it is 24.

You just plug it in.

You welcome

7 0

4 years ago

A number is being multiplied by a power of 10. Find the number.

alexira [117]

Answer: a:7 b:36 c:4

Step-by-step explanation:

the exponents are the amount of 0s you put behind the number.

ex: 10 to the power of 4: 10,000, 4 zeroes.

3 0

3 years ago

Families USA, a monthly magazine that discusses issues related to health and health costs, surveyed 20 of its subscribers. It fo

Harman [31]

Answer:

(a) The 90 percent confidence interval for the population mean yearly premium is ($10,974.53, $10983.47).

(b) The sample size required is 107.

Step-by-step explanation:

(a)

The (1 - α)% confidence interval for population mean is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

Given:

$\bar x=\$10,979\\s=\$1000\\n=20$

Compute the critical value of t for 90% confidence level as follows:

$t_{\alpha/2, (n-1)}=t_{0.10/2, (20-1)}=t_{0.05, 19}=1.729$

*Use a t-table.

Compute the 90% confidence interval for population mean as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

$=10979\pm 1.729\times \frac{1000}{\sqrt{20}}\\=10979\pm4.47\\ =(10974.53, 10983.47)$

Thus, the 90 percent confidence interval for the population mean yearly premium is ($10,974.53, $10983.47).

(b)

The margin of error is provided as:

MOE = $250

The confidence level is, 99%.

The critical value of z for 99% confidence level is:

$z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$

Compute the sample size as follows:

$MOE= z_{\alpha/2}\times \frac{s}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times s}{MOE} ]^{2}$

$=[\frac{2.58\times 1000}{250}]^{2}$

$=106.5024\\\approx107$

Thus, the sample size required is 107.

4 0

3 years ago