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Korvikt [17]
3 years ago
5

Explain, in terms of intermolecular forces, why ammonia has a higher boiling point than the other compounds in the ta

Chemistry
1 answer:
Kobotan [32]3 years ago
7 0
Answer is: ammonia has a higher boiling point because it has stronger intermolecular forces.

Intermolecular forces<span> are the forces between </span><span>molecules. The stronger are intermolecular forces, the higher is boiling point of compound, because more energy is needed to break interaction between molecules.
</span>There are several types of intermolecular forces: hydrogen bonding, i<span>on-induced dipole forces, ion-dipole forces andvan der Waals forces.</span>
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Atoms of which element have the greatest tendency to gain electrons?
Anastasy [175]
Fluorine. 

Because:- Atoms want to become stable, for an atom to become stable, they need 8 valence electrons. Since Fluorine has 7 valence electrons, it only needs one more electron to become stable and have an octet. An octet is when an atom/element has 8 valence electrons. Since Fluorine will need to gain an electron, it will have a negative charge, and become an anion. 
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3 years ago
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What is the one variable that is changed in the experimental group called? the placebo the independent variable the control grou
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Answer:

the independant variable

Explanation:

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3 years ago
75.0 grams of MgCl, is dissolved in 500.0 g of water, density 1.00 g/ml. What is the MOLALITY of this solution?
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Answer:

C

Explanation:

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8 0
2 years ago
Determine the molar concentration of na+ and po4 3- in a 2.25 M Na3 PO4 solution
muminat

Answer:

A. The concentration of Na^+ in the solution is 6.75 M.

B. The concentration of PO4^3- in the solution is 2.25 M.

Explanation:

We'll begin by writing the balanced dissociation equation for Na3PO4.

This is illustrated below:

Na3PO4 will dissociate in solution as follow:

Na3PO4(aq) —> 3Na^+(aq) + PO4^3-(aq)

Thus, from the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+ and 1 mole of PO4^3-

A. Determination of the concentration of Na+ in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+.

Therefore, 2.25 M Na3PO4 solution will produce = (2.25 x 3) /1 = 6.75 M Na^+.

Therefore, the concentration of Na^+ in the solution is 6.75 M

B. Determination of the concentration of PO4^3- in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 1 mole of PO4^3-

Therefore, 2.25 M Na3PO4 solution will also produce 2.25 M PO4^3-.

Therefore, the concentration of PO4^3- in the solution is 2.25 M.

7 0
3 years ago
Place each statement in the column of the particle that it best describes.<br> Refer To Photo
MrRa [10]

The options are labelled as:

1     2

3    4

5    6

7    8

Protons: 1, 5, 7

Neutrons: 2, 8

Electron: 3, 4, 6

5 0
3 years ago
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