Answer:
Ionic
Explanation:
If A does not have electron to bond, it just receives one electron from B.
It can´t be covalent because A don´t have any electrons to bond with B.
I'm going on a limb here, but Carbon is a definite. <span />
Answer:
Explanation:
A t-test is a type of inferential statistic used to determine if there is a significant difference between the means of two groups, which may be related in certain features. The t-test is one of many tests used for the purpose of hypothesis testing in statistics. Calculating a t-test requires three key data values.
Answer:
mass = 1.8x10⁻³ kg; number of moles = 4.1x10⁻⁵ kmol; specific volume = 0.55 m³/kg; molar specific volume = 24.4 m³/kmol
Explanation:
By the Avogadro's number, 1 mol of the matter has 6.02x10²³ molecules, thus, the number of moles (n) is the number of molecules presented divided by Avogadro's number:
n = 2.5x10²²/6.02x10²³
n = 0.041 mol
n = 4.1x10⁻⁵ kmol
The molar mass of CO₂ is 44 g/mol (12 g/mol of C + 2*16g/mol of O), and the mass is the number of moles multiplied by the molar mass:
m = 0.041 mol * 44 g/mol
m = 1.804 g
m = 1.8x10⁻³ kg
The specific volume (v) is the volume (1L = 0.001 m³) divided by the mass, and it represents how much volume is presented in each part of the mass:
v = 0.001/1.8x10⁻³
v = 0.55 m³/kg
The molar specific volume (nv) is the volume divided by the number of moles, and it represents how much volume is presented in each part of the mol:
nv = 0.001/4.1x10⁻⁵
nv = 24.4 m³/kmol
Answer:
Molarity of the packet is 0.5M
Explanation:
In the reaction of acetic acid with NaOH:
CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺
<em>1 mole of acetic acid reacts with 1 mole of NaOH.</em>
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When you are titrating the acid with NaOH, you reach equivalence point when moles of acid = moles of NaOH.
Moles of NaOH are:
3.0mL = 3.0x10⁻³L ₓ (0.1 mol / L) =<em> 3.0x10⁻⁴ moles</em> of NaOH = moles of CH₃COOH.
Now, you find the moles of acetic acid in the hot sauce packet. But molarity is the ratio between moles of the acid and liters of solution.
As you don't know the volume of your packet, <em>you can assume its density as 1g/mL. </em>Thus, volume of 0.6g of hot sauce is 0.6mL = 6x10⁻⁴L.
And molarity of the packet is:
3.0x10⁻⁴ moles acetic acid / 6x10⁻⁴L =
<h3>0.5M</h3>