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olga2289 [7]
3 years ago
12

Explain the difference between an organic compound and a hydrocarbon

Chemistry
1 answer:
VLD [36.1K]3 years ago
4 0
An organic compound<span> is any member of a large class of gaseous, liquid, or solid chemical </span>compounds whose molecules contain carbon and <span>a hydrocarbon is compound of hydrogen and carbon, such as any of those that are the chief components of petroleum and natural gas.</span>
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juin [17]



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5 0
2 years ago
Plz help all chemist!
solmaris [256]

Answer:

D. bromine

Explanation:

Highest electronegativity in the period has element closest to the *A group

K Ca Cu Br

6 0
3 years ago
The reaction of glucose, c6h12o6, with oxygen produces carbon dioxide and water. what is the sum of the coefficients in the bala
Misha Larkins [42]

The balanced equation for the given reaction:

C₆H₁₂O₆ (glucose) + 6O₂→ 6CO₂ + 6H₂O

So in the balanced equation the coefficients before glucose, oxygen, water and carbon dioxide are 1, 6, 6 and 6 respectively.

Therefore, the sum of the coefficients in the balanced equation

= 1 + 6 + 6 + 6

= 19

The correct answer is 19.

8 0
3 years ago
What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest whole-number coeffici
rodikova [14]

Answer:

Option (B) 7

Explanation:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)

There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)

Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

7 0
3 years ago
If the relative activities of two metals are known which metal is more easily oxidized
Ksivusya [100]
Answer: The metal that has a greater reactivity is more easily oxidized.

Explanation:

Oxidation is when the elements lose electrons and increase their oxidation state.

The metals tend to react by losing electrons and form the corresponding cation.

For expample, sodium (an alkalyne metal) loses one elecron and form the cation Na¹⁺ , then this cation combine with an anion and form compounds like NaCl, NaOH. The same do the other alkalyne metals.

Magnesium (an alkalyne earth metal) loses two electrons and form the cation Mg²⁺, then it combines with some anions to form compounds, like MgSO₄, Mg(OH)₂.

So, the easier the metal gets oxidized the greater its reactivity.




6 0
3 years ago
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