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olga2289 [7]
3 years ago
12

Explain the difference between an organic compound and a hydrocarbon

Chemistry
1 answer:
VLD [36.1K]3 years ago
4 0
An organic compound<span> is any member of a large class of gaseous, liquid, or solid chemical </span>compounds whose molecules contain carbon and <span>a hydrocarbon is compound of hydrogen and carbon, such as any of those that are the chief components of petroleum and natural gas.</span>
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Low-cost energy. Although building nuclear power plants has a high initial cost, it's relatively cheap to produce energy from them and they have low operating costs.

Reliable.

Zero carbon emissions.

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High energy density.

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2 years ago
What might be a scientific question
AURORKA [14]

Answer:

Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

Explanation:

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1 year ago
15. What is true about concentration of a solution? *
Naya [18.7K]
<h3>Answer:</h3>

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

<h3>Explanation:</h3>
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8 0
3 years ago
PLEASE HELP MY TEACHER IS GOING TO SEE ME AFTER CLASS
Crazy boy [7]

Answer:

The Nucelous helps prevent bad cells in

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6 0
2 years ago
A chemist wishing to do an experiment requiring 47-Ca2+ (half-life = 4.5 days) needs 5.0 μg of the nuclide. What mass of 47-CaCO
NARA [144]

Answer:

5.8μg

Explanation:

According to the rate or decay law:

N/N₀ = exp(-λt)------------------------------- (1)

Where N = Current quantity,  μg

            N₀ = Original quantity, μg

             λ= Decay constant day⁻¹

              t =  time in days

Since the half life is 4.5 days, we can calculate the  λ from (1) by  substituting N/N₀ = 0.5

0.5 = exp (-4.5λ)

ln 0.5  = -4.5λ

-0.6931 = -4.5λ

λ =   -0.6931 /-4.5

  =0.1540 day⁻¹

Substituting into (1)  we have :

N/N₀ = exp(-0.154t)----------------------------- (2)

To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:

N = 5.0 μg

N₀ = Unknown

t = 1 day

Substituting into (2) we have

[5/N₀]   = exp (-0.154 x 1)

    5/N₀        = 0.8572

N₀  =  5/0.8572

     =    5.8329μg

    ≈     5.8μg

The Chemist must order 5.8μg  of 47-CaCO3

6 0
2 years ago
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