Answer:
135°
Step-by-step Explanation:
==>Given:
An inscribed quadrilateral ABCD with,
m<A = (3x +6)°
m<C = (x + 2)°
==>Required:
measure of angle A
==>Solution:
First, let's find the value of x.
Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.
Therefore, this means m<A + m<C = 180°
Thus, (3x+6) + (x+2} = 180
3x + 6 + x + 2 = 180
Collect like terms:
3x + x + 6 + 2 = 180
4x + 8 = 180
Subtract 8 from both sides:
4x + 8 - 8 = 180 - 8
4x = 172
Divide both sides by 4:
4x/4 = 172/4
x = 43
We can now find m<A = (3x + 6)°
m<A = 3(43) + 6
= 129 + 6
measure of angle A = 135°
Equation of the line in point slope form is y + 3 = -1/2(x - 7)
Step-by-step explanation:
- Step 1: Given slope of the line is -1/2 and passes through the point (x1, y1) = (7, -3). Equation in point slope form is y - y1 = m(x - x1)
⇒ y - (-3) = -1/2(x - 7)
⇒ y + 3 = -1/2(x - 7)
Answer:
12 : 4.92
Step-by-step explanation:
a= apples
12a=4.92
12 : 4.92
Answer:
5 * 10^10
Step-by-step explanation:
that's it bro. learn how to do it. then you won't need brainly anymore foo'.
You have the correct axis of symmetry value. Nice work.
Plug that x value into the equation to get...
y = -2x^2 - 12x - 10
y = -2*(-3)^2 - 12*(-3) - 10 <<-- replace every x with -3; then use PEMDAS
y = -2*(9) - 12*(-3) - 10
y = -18 + 36 - 10
y = 18 - 10
y = 8
The vertex is the ordered pair (-3, 8)
Note: the axis of symmetry is the vertical line through the vertex
