All categories

4 years ago

What can a doctor use to determine a patient's body fat percentage?

Mathematics

2 answers:

Leya [2.2K]4 years ago

7 0

Bioelectrical impedance machine

That is definitely the answer, so A not B

Reptile [31]4 years ago

4 0

It is Bioelectrical impedance machine, these devices are used to measure the percentage of fat on your body so it is B

You might be interested in

What is the solution to y=3x-1 ?

Iteru [2.4K]

I'm ASSUMING that we're talking about Three Ordered Ordered Pair Solutions.

If so, the answer is (0,−1),(1,2),(2,5).

8 0

3 years ago

Read 2 more answers

Which relation is a function ?

Leokris [45]

Answer:

Bottom left

Step-by-step explanation:

If you can draw a vertical line through a graph and touch only one point, the relation is a function.

3 0

4 years ago

Help me please i need to pass

Alekssandra [29.7K]

mCAX is the same as mBAX so the answer would be 32 degrees

8 0

3 years ago

ILL MARK BRAINLEST JUST HELP PLEASEEE

krek1111 [17]

Answer:

I think its 336. I might be wrong though, But I hope I am right.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

Using first principle, this gives:

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

Hence, the smallest sum is 2

3 0

3 years ago