Write a loop that displays all possible combinations of two letters where the letters are 'a', or 'b', or 'c', or 'd', or 'e'. T
1 answer:
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Answer:
while(is_sunny=="n")
Explanation:
The loop keeps repeating itself until a certain condition is met.
Here while loop keeps executing until value of is_sunny is not equal to 'n'
When the value of is_sunny is not equal to n then the loop stops.
So lets explain this logic with a chunk of code:
#include <iostream> //to use input output functions
using namespace std; //to identify objects like cin cout
int main() { //start of main function
string is_sunny = "n"; //value of is_sunny is set to n
cout<<"Enter value of is_sunny: "; // prompts user to enter value of is_sunny
cin>>is_sunny; // reads value of is_sunny from user
while(is_sunny=="n") // keeps iterating until value of is_sunny is not equal to n
{ cout<<"keep executing until is_sunny is not equal to n"<<endl;//display this message with each iteration
cout<<"Enter value of is_sunny: "; //keeps prompting to enter is_sunny
cin>>is_sunny; } } //keeps reading value of is_sunny from user
Now if the user keeps entering "n" as value of is_sunny then the loop keeps repeating. When the user enters any string other than n then the loop breaks. The output of the program is attached.
