The answer to this question is "repairing old appliances"
Answer:
did you get the answer yet
Answer:
Part A: Thr-Leu-Val
Part B: ACC-UUG-GUU
Explanation:
When you transcribe a DNA sequence to mRNA, you need to remember that in RNA there is no Thymine (T), instead it has Uracil (U). So the base pairings would be like this compared to DNA base pairing:
DNA RNA
A-T A-U
T-A T-A
C-G G-C
G-C C-G
Given the sequence the transcription will be as follows:
DNA : TGG - AAC - CAA
mRNA: ACC - UUG - GUU
Next, to translate it into amino acids, you will use the chart. Now amino acids pair in codons (3 base pairs at a time). Let's take the first codon in your sequence:
ACC
1st 2nd 3rd
A C C
Using the column on the left, find the row that matches it, so in this case A.
At the very top, there is another row of letters, looking at the row of A only, look for the column of the second base which is C.
Lastly, look at the right most column and find the letter that matches the third base within the box where A and C intersect. In this case, C is your third base.
The amino acid where all three intersect is your first amino acid which is Thr.
Just do this for the next codons and you will come up with the answer.
Layering.
Hope this helps (:
-Payshence xoxo
Answer:
The answer to your question is:
Explanation:
Two molecules with the chemical formulas C₆H₁₂O₆ and C₆H₁₂O₂ are probably monosaccharides.
Monosaccharides is the basic unit of carbohydrates. All monosaccharides have the formula (CH₂O)
.
Monosaccharides most important are glucose, fructose, etc.
