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WARRIOR [948]
3 years ago
6

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
2 answers:
lana [24]3 years ago
6 0

Answer:

13

Step-by-step explanation:

The difference between the x-values is 5.

The difference between the y-values is 12.

These are the non-hypotenuse sides.

12^2 + 5^2 = c^2

144 + 25 = c^2

169 = c^2

c = 13

The distance between the two points is 13.

Genrish500 [490]3 years ago
4 0

Answer:

13 units

Step-by-step explanation:

(-1,5) and (4, -7)

To find the distance of two points, we use the distance formula:

d = \sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2 }

Let's plug in what we know.

d = \sqrt{(4 - (-1))^2 + (-7 - 5)^2 }

Evaluate the double negative.

d = \sqrt{(4 +1))^2 + (-7 - 5)^2 }

Evaluate the parentheses.

d = \sqrt{(5)^2 + (-12)^2 }

Evaluate the exponents.

d = \sqrt{(25) + (144) }

Add.

d = \sqrt{(169) }

Evaluate the square root.

d = 13

13 units

Hope this helps!

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Answer:

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17.5 cups of flower is used with 7 cups of sugar.

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3 years ago
If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

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Substitute h(t) = 0 in above function.

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Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

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3 years ago
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