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shtirl [24]
3 years ago
5

Which is the slope of the line that passes through the points (−3,1) and (4,−2)?

Mathematics
2 answers:
Elis [28]3 years ago
5 0
Hello!

Here is the formula for finding slope:

<u>y₂ - y₁</u>
x₂ - x₁

OR

<u>difference in y</u>
difference in x
__________________________________________________________

y₂ = -2
y₁ = 1

(-2) - 1 = -2 + -1 = -3

x₂ = 4
x₁ = -3

4 - (-3) = 4 + 3 = 7

That equals: -3/7

\framebox{Slope = -3/7}
Rasek [7]3 years ago
4 0

Finding the slope using two points:

The formula for slope is

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

In this case...

y_{2} =-2\\y_{1} =1\\x_{2} =4\\x_{1} =-3

^^^Plug these numbers into the formula for slope...

\frac{-2-1}{4 - (-3)}

\frac{-3}{7}

^^^This is your slope

Hope this helped!

~Just a girl in love with Shawn Mendes

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A satellite orbits the Earth with an elliptical orbit modeled by x squared over 43 million eight hundred twenty four thousand fo
morpeh [17]

"For a satellite orbit, the Earth with an elliptical orbit modeled by..." the maximum distance between the satellite and the Earth is

D= 510 km. Option B. This is further explained below.

<h3>What is Kepler Orbit?</h3>

Generally, In the study of astrodynamics, an ellipse of the satellite is often referred to as a Kepler Orbit

The function of the elliptical orbit is

\frac{(x-h)^2}{a^2}+\frac{(x-k)^2}{b^2}=1

compared to

\frac{(x^2)^2}{47334400}+\frac{(y^2)^2}{43956900}=1

Hence

a = √(47,334,400 km²)

a= 6,880 km.

In conclusion, The distance of the satellite above the Earth's surface.

D = a - r

D= 6,880 km - 6,370 km

D= 510 km

Read more about elliptical orbit

at brainly.com/question/13999216

#SPJ1

7 0
2 years ago
Read 2 more answers
Sheila buys some boxes of pens, with 20 pens in each box.
Bond [772]
Take the number of pen per box and multiply by the number of boxes giving you the total number of pens bought
5 0
3 years ago
Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. ​(a) Descr
Daniel [21]

Answer:

(a) The sampling distribution of\overline{X} = Population mean = 79

(b)  P ( \overline{X} greater than 81.2 ) =  0.1357

(c) P (\overline{X} less than or equals 74.4 ) = .0107

(d) P (77.6 less than \overline{X} less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean (\nu) = 79

Standard deviation (\sigma ) = 18

​(a) Describe the sampling distribution of \overline{X}

For large sample using central limit theorem

the sampling distribution of\overline{X} = Population mean = 79

​(b) What is Upper P ( \overline{X} greater than 81.2 )​ =

P(\overline{X}> 81.2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})

                    =  P(Z> 1.1)

                    = 1 - P(Z<   1.1)

                    = 1 - .8643 =

                    = 0.1357

(c) What is Upper P (\overline{X} less than or equals 74.4 ) =

P(\overline{X}\leq  74.4) = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{74.4- 79}{\frac{18}{\sqrt{81}}})

                    = P(Z\leq  -2.3)

                    = .0107

​(d) What is Upper P (77.6 less than \overline{X} less than 83.2 ) =

P(77.6< \overline{X}<   83.2) = P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{83.2- 79}{\frac{18}{\sqrt{81}}})

                                = P(- 0.7< Z<   2.1)

                                 = (Z<   2.1) - (Z<   -0.7)

                                  = 0.9821 - .2420

                                   = 0.7401

3 0
3 years ago
Factor completely x2 - 16y2
Y_Kistochka [10]

Answer:

(x+4y)(x-4y)

Step-by-step explanation:

Since

\large a^2-b^2=(a+b)(a-b)

we can see that

\large x^2-16y^2=(x+4y)(x-4y)

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3 years ago
CAN SOMEONE JUST CHECK MY ANSWER?
12345 [234]

Answer:

you are absolutely correct .........

6 0
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