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2 years ago

The bases of a trapezoid have lengths 10 and 18. If the height of the trapezoid is 6, what is the area of the trapezoid

Mathematics

1 answer:

vladimir1956 [14]2 years ago

6 0

Answer:

Step-by-step explanation:

The bases of a trapezoid have lengths 10 and 18. If the height of the trapezoid is 6, what is the area of the trapezoid

The area of a trapezoid is given as:

1/2(b1 + b) × h

Where:

b1 = Base 1 = 10

b2= Base 2 = 18

h = Height = 6

Therefore, the area of a trapezoid =

1/2 (10 + 18) × 6

= 28/2 × 6

= 84

Therefore, the area of the trapezoid = 84

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A metal plate measuring 32cm by 12cm is cut into

Reil [10]

Answer:

Step-by-step explanation:

First find the area of the metal plate: 32*12=384

Find the are of each small square to see how much space it takes: 4*4=16

Divide the two to see how many can fit: 24

Tell me if you have any questions!

5 0

3 years ago

Read 2 more answers

Con

mr Goodwill [35]

Answer:

The coordinates of E are $E(x,y) = \left(\frac{9}{2}, 0 \right)$ .

Step-by-step explanation:

The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.

Vectorially speaking, dilation is defined by the following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y) - O(x,y)]$ (1)

Where:

$O(x,y)$ - Point of reference.

$P(x,y)$ - Original point.

$P'(x,y)$ - Dilated point.

$k$ - Dilation factor.

By applying this operation, point B becomes point D:

$B(x,y) = (0,4)$ , $D(x,y) = (0,6)$

$D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]$

$D(x,y) = (0,0) + k\cdot (0,4)$

$(0,6) = (0,0) +(0,4\cdot k)$

$(0, 6) = (0,4\cdot k)$

$k = \frac{3}{2}$

Lastly, we transform point C into point E by applying the same operation: $C(x,y) = (3, 0)$ , $O(x,y) = (0,0)$ and $k = \frac{3}{2}$

$E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]$

$E(x,y) = \left(\frac{9}{2}, 0 \right)$

The coordinates of E are $E(x,y) = \left(\frac{9}{2}, 0 \right)$ .

8 0

3 years ago

If you stacked Avogadro's number of pennies one on top of the other on Earth's surface, how far would the stack extend (in kilom

miskamm [114]

Answer:my

The height of the stack will be 9.15×10^20_m

Or 9.15×10^17_Km

Which is 6 billion times more more than the distance to the sun

Or 22.9 million times further than the star Proxima Centauri

Step-by-step explanation:

Given

Avogadro's number = 6.02×10^23 particles

And the thickness of a penny = 1.52_mm

The height of the stack will be

1.52 × 6.02 ×10^23 = 9.15×10^23_mm 9.15×10^20_m

7 0

3 years ago

(12,10),(-2,r), m=-4

Savatey [412]

Answer:66

Step-by-step explanation:

Y=mx+b

10=-4*12+b

10=-48+b

b=58

r=-4(-2)+58

r=66

4 0

3 years ago

I need some help with these please :')

Nataly [62]

Step-by-step explanation:

problem 1.

1. 6y = 30

2. y = 5

3. 3x + 2(5) = 16

4. 3x+10=16

5. 3x=6

6. x=2

solution: (2,5)

problem 2.

1. x=7

2. 4(2)-2y=18

3. 28-2y=18

4. -2y= -10

5. y=5

solution (7,5)

problem 3

10x=10

x=1

7(1) +y =-2

y=-9

(1,9)

problem 4

0= -6

no solution

problem 5

0=0

Infinite many

5 0

2 years ago