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pychu [463]
3 years ago
9

You run an experiment to test the effects of temperature on solubility. What would you heat? A.) solvent B.) solute C.) the room

B.) the beaker
Chemistry
2 answers:
taurus [48]3 years ago
8 0
The most appropriate answer is A !!

As solvent temp is increased the solubility of solute increases !!
Vilka [71]3 years ago
4 0

Answer:

The correct answers is A) solvent.

Explanation:

Solubility is the ability of a substance to dissolve in another called solvent. The solubility of a solute in a given solvent mainly depends on the temperature. For many solids dissolved in liquid water, solubility increases with temperature up to 100 ° C.

In the liquid water at high temperatures the solubility of the ionic solutes tends to decrease due to the change in the properties and structure of the liquid water.

Gaseous solutes show a more complex behavior with temperature. As the temperature rises, the gases generally become less soluble in water but more soluble in organic solvents.

Hence, if we vary the temperature of the solvent we can check the effects on solubility of a solute.

You might be interested in
Phenolphthalein has a pKa of 9.7 and is colorless in its acid form and pink in its basic form. calculate [In-}/{HIn} for the fol
zvonat [6]

Answer:

1.58x10⁻⁵

2.51x10⁻⁸

0.0126

63.10

Explanation:

Phenolphthalein acts like a weak acid, so in aqueous solution, it has an acid form HIn, and the conjugate base In-, and the pH of it can be calculated by the Handerson-Halsebach equation:

pH = pKa + log[In-]/[HIn]

pKa = -logKa, and Ka is the equilibrium constant of the dissociation of the acid. [X] is the concentrantion of X. Thus,

i) pH = 4.9

4.9 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = - 4.8

[In-]/[HIn] = 10^{-4.8}

[In-]/[HIn] = 1.58x10⁻⁵

ii) pH = 2.1

2.1 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -7.6

[In-]/[HIn] = 10^{-7.6}

[In-]/[HIn] = 2.51x10⁻⁸

iii) pH = 7.8

7.8 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -1.9

[In-]/[HIn] = 10^{-1.9}

[In-]/[HIn] = 0.0126

iv) pH = 11.5

11.5 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = 1.8

[In-]/[HIn] = 10^{1.8}

[In-]/[HIn] = 63.10

6 0
3 years ago
What energy conversion takes place<br> as a leaf falls to the ground?
Zigmanuir [339]

Answer:

<h3>The answer is kinetic energy</h3>

Explanation:

<h2>The answer is Kinetic Energy because take for an example,  When an apple falls from the tree to the ground, its energy of position is then made into kinetic energy, the energy of motion, as it falls to the ground. </h2>

------------------------------------------------------------------------------------------------

Hope this helps! Give me Brainliest if u can!

4 0
3 years ago
Read 2 more answers
Which of the following represents the correct ranking in terms of increasing boiling point? A. n-butane &lt; 1-butanol &lt; diet
bonufazy [111]

Answer:

The answer to your question is: letter E

Explanation:

Normally, the correct order of boiling points is:

                     Alcohols > Ketones > Ether > Alkane

Then

A. n-butane < 1-butanol < diethyl ether < 2-butanone

B. n-butane < 2-butanone < diethyl ether < 1-butanol

C. 2-butanone < n-butane < diethyl ether < 1-butanol

D. n-butane < diethyl ether < 1-butanol < 2-butanone

E. n-butane < diethyl ether < 2-butanone < 1-butanol

     (- 1°C)     <    34.6°C         <  79.64°C      <  117.7°C

6 0
3 years ago
What causes the oceans in polar regions to be cooler than oceans near the equator
Olenka [21]
The global wind patterns cause the surface currents to form in the uppers layer of the ocean.
7 0
3 years ago
Qual a relação e as PROPORÇÕES entre Joules, cal, Cal, e Kcal?
RUDIKE [14]

Answer:

Check Explanation

Verificar explicação

Explanation:

English Translation

What is the relationship and the PROPORTIONS between Joules, lime, Cal, and Kcal?

Joules is the SI unit of Energy (heat energy).

Calorie, also called lime, is the amount of heat required to raise the temperature of 1 gram of pure water by 1°C or 1 K.

1 calorie = 4.186 J

A thousand calorie is equal to 1 kcal.

Hence,

1 kcal = 1000 calories = 4186 J

In Portugese/Em português

Joules é a unidade SI de energia (energia térmica).

Caloria, também chamada de cal, é a quantidade de calor necessária para elevar a temperatura de 1 grama de água pura em 1°C ou 1 K.

1 caloria = 4,186 J

Mil calorias é igual a 1 kcal.

Portanto,

1 kcal = 1000 calorias = 4186 J

Hope this Helps!!!

Espero que isto ajude

6 0
3 years ago
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