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pychu [463]
2 years ago
9

You run an experiment to test the effects of temperature on solubility. What would you heat? A.) solvent B.) solute C.) the room

B.) the beaker
Chemistry
2 answers:
taurus [48]2 years ago
8 0
The most appropriate answer is A !!

As solvent temp is increased the solubility of solute increases !!
Vilka [71]2 years ago
4 0

Answer:

The correct answers is A) solvent.

Explanation:

Solubility is the ability of a substance to dissolve in another called solvent. The solubility of a solute in a given solvent mainly depends on the temperature. For many solids dissolved in liquid water, solubility increases with temperature up to 100 ° C.

In the liquid water at high temperatures the solubility of the ionic solutes tends to decrease due to the change in the properties and structure of the liquid water.

Gaseous solutes show a more complex behavior with temperature. As the temperature rises, the gases generally become less soluble in water but more soluble in organic solvents.

Hence, if we vary the temperature of the solvent we can check the effects on solubility of a solute.

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Calculate the amount of heat required to completely sublime 55.0 g of solid dry ice CO2 at its sublimation temperature. The heat
aliina [53]

Answer:

40.4 kJ

Explanation:

Step 1: Given data

  • Mass of CO₂ (m): 55.0 g
  • Heat of sublimation of CO₂ (ΔH°sub): 32.3 kJ/mol

Step 2: Calculate the moles corresponding to 55.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

n = 55.0 g × 1 mol/44.01 g = 1.25 mol

Step 3: Calculate the heat (Q) required to sublimate 1.25 moles of CO₂

We will use the following expression.

Q = n × ΔH°sub

Q = 1.25 mol × 32.3 kJ/mol = 40.4 kJ

7 0
2 years ago
A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
Karo-lina-s [1.5K]

Answer:

k= 1.925×10^-4 s^-1

1.2 ×10^20 atoms/s

Explanation:

From the information provided;

t1/2=Half life= 1.00 hour or 3600 seconds

Then;

t1/2= 0.693/k

Where k= rate constant

k= 0.693/t1/2 = 0.693/3600

k= 1.925×10^-4 s^-1

Since 1 mole of the nuclide contains 6.02×10^23 atoms

Rate of decay= rate constant × number of atoms

Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms

Rate of decay= 1.2 ×10^20 atoms/s

8 0
2 years ago
A mixture of 9.22 moles of A, 10.11 moles of B, and 27.83 moles of C is placed in a one-liter
AysviL [449]

The equilibrium constant is 1.3 considering the reaction as written in the question.

<h3>Equilibrium in chemical reactions</h3>

In a chemical reaction, the equilibrium constant is calculated based on the equilibrium concentration of each specie. The equation of this reaction is;

A (g) + 2B (g) ⇌ 3C (g).

The initial concentration of each specie is;

  • A - 9.22 M
  • B - 10.11 M
  • C - 27.83 M

The equilibrium concentration of B is 18.32 M

We now have to set up the ICE table as follows;

         A (g) +    2B (g) ⇌     3C (g)

I       9.22        10.11           27.83

C     -x              -x                +x

E   9.22 - x       10.11 - x       27.83 + x

The equilibrium concentration of B is 18.32 M hence;

10.11 - x = 18.32

x = 10.11 - 18.32 = -8.21

Hence;

Equilibrium concentration of A = 9.22 - (-8.21) = 17.43

Equilibrium concentration of C = 27.83 + (-8.21) = 19.62

Equilibrium constant K = [19.62]^3/[17.43] [18.32]^2

K = 1.3

Learn more about equilibrium constant: brainly.com/question/17960050

4 0
2 years ago
Help!! I’ll give Brainly!!
goldenfox [79]
Hey not really an answer but just needed someone to talk to you
8 0
3 years ago
What substance is reduced in the reaction 2Fe2+ + Cl2 → 2Fe3+ + 2Cl−?
Vladimir [108]

Answer:

Cl2, because it gained electrons

Explanation:

2Fe^2+ went from 2+ to 3+

Cl2 went from 0 to -1

Reduction-gain

Oxidation-loss

- means gained and + means loss trust me it doesn't make sense but if you stick to it it'll be a lot easier for you.

7 0
3 years ago
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