Answer:
40.4 kJ
Explanation:
Step 1: Given data
- Heat of sublimation of CO₂ (ΔH°sub): 32.3 kJ/mol
Step 2: Calculate the moles corresponding to 55.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
n = 55.0 g × 1 mol/44.01 g = 1.25 mol
Step 3: Calculate the heat (Q) required to sublimate 1.25 moles of CO₂
We will use the following expression.
Q = n × ΔH°sub
Q = 1.25 mol × 32.3 kJ/mol = 40.4 kJ
Answer:
k= 1.925×10^-4 s^-1
1.2 ×10^20 atoms/s
Explanation:
From the information provided;
t1/2=Half life= 1.00 hour or 3600 seconds
Then;
t1/2= 0.693/k
Where k= rate constant
k= 0.693/t1/2 = 0.693/3600
k= 1.925×10^-4 s^-1
Since 1 mole of the nuclide contains 6.02×10^23 atoms
Rate of decay= rate constant × number of atoms
Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms
Rate of decay= 1.2 ×10^20 atoms/s
The equilibrium constant is 1.3 considering the reaction as written in the question.
<h3>Equilibrium in chemical reactions</h3>
In a chemical reaction, the equilibrium constant is calculated based on the equilibrium concentration of each specie. The equation of this reaction is;
A (g) + 2B (g) ⇌ 3C (g).
The initial concentration of each specie is;
- A - 9.22 M
- B - 10.11 M
- C - 27.83 M
The equilibrium concentration of B is 18.32 M
We now have to set up the ICE table as follows;
A (g) + 2B (g) ⇌ 3C (g)
I 9.22 10.11 27.83
C -x -x +x
E 9.22 - x 10.11 - x 27.83 + x
The equilibrium concentration of B is 18.32 M hence;
10.11 - x = 18.32
x = 10.11 - 18.32 = -8.21
Hence;
Equilibrium concentration of A = 9.22 - (-8.21) = 17.43
Equilibrium concentration of C = 27.83 + (-8.21) = 19.62
Equilibrium constant K = [19.62]^3/[17.43] [18.32]^2
K = 1.3
Learn more about equilibrium constant: brainly.com/question/17960050
Hey not really an answer but just needed someone to talk to you
Answer:
Cl2, because it gained electrons
Explanation:
2Fe^2+ went from 2+ to 3+
Cl2 went from 0 to -1
Reduction-gain
Oxidation-loss
- means gained and + means loss trust me it doesn't make sense but if you stick to it it'll be a lot easier for you.
