Answer:
We need 10.14 grams of sodium bromide to make a 0.730 M solution
Explanation:
Step 1: Data given
Molarity of the sodium bromide (NaBr) = 0.730 M
Volume of the sodium bromide solution = 135 mL = 0.135 L
Molar mass sodium bromide (NaBr) = 102.89 g/mol
Step 2: Calculate moles NaBr
Moles NaBr = Molarity NaBr * volume NaBr
Moles NaBr = 0.730 M * 0.135 L
Moles NaBr = 0.09855 moles
Step 3: Calculate mass of NaBr
Mass NaBr = 0.09855 moles * 102.89 g/mol
Mass NaBr = 10.14 grams
We need 10.14 grams of sodium bromide to make a 0.730 M solution
B, they belong to group 1
A: Li is period 2 and Na is period 3
C: Na has one more electron shell
D: Not related to how it is spelled
Answer:
all of the above. they all are chemical reactions
Answer:
Cation
Explanation:
Since the protons are greater than electrons, this means the atom has a net positive charge on it and is now called a cation.
As there are 4 protons, this means that the outermost shell has 2 valence electrons 2s1, 2s2 and this is Group 2 element. Looking at Periodic table, we find that this is beryllium 4Be5 and is denoted as Be^2+
