Answer:
C. Aluminum
Explanation:
Aluminum has 5.9858 ionization energy
Boron has 8.298 ionization energy
Silicon has 8.1517 ionization energy
Carbon has 11.2603 ionization energy
The isotope is identified as 58 Fe²⁺, where 58 is the mass number of the isotope.
Explanation:
In this problem, there is difference in the number of protons and electrons, but the electron number should not vary in a stable isotope. As isotopes are meant to have difference in number of neutrons leading to change in the mass number. So this means, in the present case the isotope is in oxidized state as the number of electrons is less than the number of protons. This indicates that the isotope is in +2 oxidation state, since the difference in the number of protons and electrons is 2.
Then as an isotope will be formed by varying in the number of neutrons for the elements in periodic table. So from the number of protons we can confirm the atomic number of the element. As the atomic number is given as number of protons in case of oxidized element, the atomic number of 26 in the present case will be related to Fe element in the periodic table.
Hence the isotope will be Fe in +2 oxidation state and having the atomic number as 26 and mass number as 26+32 = 58. So there is a change in the mass number of the isotope of Fe from 56 to 58.
Thus, the isotope is identified as 58 Fe²⁺, where 58 is the mass number of the isotope.
The amount of Silicon left after 300 years is 75g
It is given that the initial amount of Si is 100 times decay is 300 years and the half-life of Silicon is 710 years.
The radioactive decay formula is given by,
A = A₀ x 2^(-t/h);
where;
A is the resulting amount after t time, Ao is the initial amt (t=0),t is the time of decay, and h is the half-life of the substance.
On substituting the values from the given we get,
A = 100x2^(-300/710)
A = 100 x 0.746112347
A = 74.6112347 grams left after 300 yrs
Therefore, the number of grams of silicon left after 300 years is 74.6112347g. This value could be rounded off to 75 grams as in the whole number
To know more about half-life, click below:
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CI2 + 2Nal ---> 2NalCI + I2
Nal = 149.9 g/mol.
NaCI = 58.5 g/mol
2 mol Nal makes 2 mol NaCI
0.29 g Nal x ( 1 mol / 149.9 g) = 0.0019 mol NaCI
00.19 mol NaCI x ( 58.5 g / 1 mol ) 0.11 g NaCI ( 2 sig figs)
Answer:
the answer would be c. plane
