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jenyasd209 [6]
3 years ago
11

How many grams are there in 7.4 x 1023 molecules of H2SO4?

Chemistry
1 answer:
bazaltina [42]3 years ago
4 0

7.4x10^23 = molecules of silver nitrate sample  

6.022x10^23 number of molecules per mole (Avogadro's number)  

Divide molecules of AgNO3 by # of molecules per mol  

7.4/6.022 = 1.229 mols AgNO3 (Sig Figs would put this at 1.3)  

(I leave off the x10^23 because they both will divide out)  

Use your periodic table to find the molar weight of silver nitrate.  

107.868(Ag) + 14(N) + 3(16[O]) = 169.868g/mol AgNO3  

Now multiply your moles of AgNO3 with your molar weight of AgNO3  

1.229mol x 169.868g/mol = 208.767g AgNO3

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In a titration experiment, 31.4 mL of 1.120 M HCOOH is neutralized by 16.3 mL of Ba(OH)2. What is the concentration of the Ba(OH
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Answer : The concentration of the Ba(OH)_2 solution is, 2.16 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCOOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2.

We are given:

n_1=1\\M_1=1.120M\\V_1=31.4mL\\n_2=2\\M_2=?\\V_2=16.3mL

Putting values in above equation, we get:

1\times 1.120M\times 31.4mL=2\times M_2\times 16.3mL\\\\M_2=2.16M

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Answer: acetone molecule ( CH₃-CO-CH₃)


Explanation:


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2) That is a molecule (build up of covalent bonds).


3) When dissolved, covalent bonded compounds remain as separate molecules, then it is said that the major species present in the solution is the molecule. The molecules of acetone are surrounded (sovated) by the molecules of water.


This as opposed to the case of ionic compounds that ionize. When a compound as NaCl dissolves in water, it ionizes completely, so the major speceies are not NaCl formulas, but the ions Na⁺ and Cl⁻, not molecules.


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