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3 years ago

What are the solution(s) to the quadratic equation 50 – x^2 = 0?

Mathematics

2 answers:

PIT_PIT [208]3 years ago

8 0

Answer:

x = 5 root 2

Step-by-step explanation:

Make the x squared positive and find the square root of 50 which is the answer.

Mumz [18]3 years ago

4 0

Answer:

5sqrt2 or -5sqrt2(It might not make sense because I couldn't really do everything on this platform but it is right)

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−x2+50=0

For this equation: a=-1, b=0, c=50

−1x2+0x+50=0

Step 2: Use quadratic formula with a=-1, b=0, c=50.

x= −b±√b2−4ac 2a

x= −(0)±√(0)2−4(−1)(50) 2(−1)

x= 0±√200 -2

x=−5√2 or x=5√2

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The lee family buys a new car that has a sales price of 35,000. If the car dealer requires minimum down payment of 15% what is t

Bad White [126]

Answer:5250.00

Step-by-step explanation: percents are a multiplication so 35,000×15=5250.00

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4 years ago

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When completing the square on the equation c2 + 110 = 12, the resulting solution is:<br> It

Delvig [45]

Answer:

$c=1$ and $c=-12$

Step-by-step explanation:

The correct equation is:

$c^2+11c=12$

To solve by completing the square method.

Solution:

We have:

$c^2+11c=12$

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

$c^2+2.\frac{11}{2}c=12$

$c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2=12$ [As $c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2$ ]

Adding both sides by $(\frac{11}{2})^2$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2$

$(c+\frac{11}{2})^2=12+\frac{121}{4}$

Taking LCD to add fraction.

$(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}$

$(c+\frac{11}{2})^2=\frac{169}{4}$

Taking square root both sides.

$\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}$

$c+\frac{11}{2}=\pm\frac{13}{2}$

Subtracting both sides by $\frac{11}{2}$ :

$c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}$

$c=\pm\frac{13}{2}-\frac{11}{2}$

So, we have:

$c=\frac{13}{2}-\frac{11}{2}$ and $c=-\frac{13}{2}-\frac{11}{2}$

$c=\frac{2}{2}$ and $c=\frac{-24}{2}$

$c=1$ and $c=-12$ (Answer)

6 0

4 years ago

Help please ITS OF TRIGONOMETRY<br>PROVE

Flauer [41]

Answer:

The equation is true.

Step-by-step explanation:

In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation. Please note that each side is named with respect to the angle is it across from.

Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

One is given the following equation,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

As per the attached reference image, one can state the following, using the right angle trigonometric ratios,

$sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}$

Substitute these values into the given equation. Then simplify the equation to prove the idenity,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

$\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}$

$1+(-1)=0$

$1-1=0$

$0=0$

7 0

3 years ago

It is believed that 43% of the US population can play the piano, 28% can play the guitar, 15% can play the harmonica, 12% can pl

melomori [17]

Answer:

The smallest sample size to satisfy the conditions is n=500.

Step-by-step explanation:

The condition for performing the inference related to the sample size is that, for all the categories, the expected success and failures in the sample are at least 10:

$np\geq10\\\\n(1-p)\geq10$

The largest sample size required will be for the minimum p or (1-p).

This happens to be the proportion that can play other instruments: 2%.

Then, we can calculate the minimum sample size as:

$np\geq10\\\\n(0.02)\geq10\\\\n\geq(10/0.02)\\\\n\geq500$

6 0

3 years ago

A candle shop sells scented candles for $16 each and unscented candles for $10 each.The shop sells 28 candles today and makes $4

fredd [130]

The number of scented candles ... x
the number of unscented candles ... y

x + y = 28
$16 * x + $10 * y = $400 ... 16 * x + 10 * y = 400

If you would like to know how many scented and how many unscented candles did the shop sell today, you can calculate this using the following steps:

x + y = 28 ... x = 28 - y
16 * x + 10 * y = 400
____________________
16 * (28 - y) + 10 * y = 400
16 * 28 - 16 * y + 10 * y = 400
448 - 400 = 16 * y - 10 * y
48 = 6 * y /6
y = 48 / 6
y = 8

x = 28 - y = 28 - 8 = 20

Result: The candle shop sold 20 scented candles and 8 unscented candles today.

8 0

3 years ago

Read 2 more answers