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Juliette [100K]
3 years ago
7

Set A={1,2,3,4,5,6} two numbers from set A are selected at random without replacement and their sum recorded how many different

sums are possible
Mathematics
1 answer:
wolverine [178]3 years ago
6 0
The minimum sum is 3 and the maximum is 11. So there are 9 different possible sums.
There are 30 ways to get these 9 different sums.
The table below shows all outcomes.

1 2 3 4 5 6
———————————-
1 | X 3 4 5 6 7
2 | 3 X 5 6 7 8
3 | 4 5 X 7 8 9
4 | 5 6 7 X 9 10
5 | 6 7 8 9 X 11
6 | 7 8 9 10 11 X
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Answer:

6\sqrt{3}i-6j

Step-by-step explanation:

Given:

The magnitude, v=12

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Now for a vector (x,y)

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Therefore:

150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}

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Similarly:

v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2

144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}

Recall that:

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Therefore: (x,y)=(6\sqrt{3}, -6)

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PLS HELP I WILL MARK BRAINLIST!!
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Answer:

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