Answer:
The 5 in 8523 is 10x greater than the 5 in 9852.
Step-by-step explanation:
Note the place value of the two number's digit 5:
8<u>5</u>23: Hundreds place value.
98<u>5</u>2: Tens place value.
10 x 10 = 100 ∴ The 5 in 8523 (hundreds place value) is 10x greater than the 5 in 9852 (tens place value).
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Answer:
x = 2
Step-by-step explanation:
Since we know one root is -3, we know one factor of the equation is (x+3)
From there we can use the factor we know to factor the rest of the equation:
x^2 + x - 6 = (x+3) * ?
Since know -6 is just 3 * -2 and since 3-2 is 1,
(x+3)(x-2) = x^2 + x - 6
From there,
x - 2 = 0
x = 2
The IQR or interquartile range is the difference between Q1 and Q3, also know as the upper and lower quartiles.
You multiply then solve for y
<span>(–9.7 • 24) • (–0.25) = –9.7 • (24 • y)
</span>-232.8*(-0.25)=-232.8y
58.2=-232.8y
58.2/-232.8=-232.8y/-232.8
y= -0.25
9514 1404 393
Answer:
2) x = 7
3) x = 5
Step-by-step explanation:
When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.
2) All of the angles are right angles.
11x +13 = 90
11x = 77 . . . . . . subtract 13
x = 7 . . . . . . . divide by 11
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3) The two marked angles are acute.
16x = 80 . . . . the acute angles are congruent
x = 5 . . . . . . divide by 16
