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riadik2000 [5.3K]
3 years ago
5

2x + 3y = 12 Complete the missing value in the solution to the equation.

Mathematics
2 answers:
Alja [10]3 years ago
8 0

Answer:

x= 6- 3y/2            y= 4- 2x/3

Step-by-step explanation:

ololo11 [35]3 years ago
5 0

Answer:

x=-6

Step-by-step explanation:

2x+3y=12

2x+3.8=12

2x+24=12

2x=-12

x=-6

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25. 1/6 3/4 2/3
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kolezko [41]

Answer:

c im quessing though but i got -54.1 so i dont know

Step-by-step explanation:

6 0
3 years ago
I need help with this
Monica [59]

Using derivatives, it is found that regarding the tangent line to the function, we have that:

  • The slope is of 962.
  • The equation of the line is y = 962x - 5119.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

The slope of the line tangent to a function f(x) at x = x' is given by f'(x'). In this problem, the function is given by:

f(x) = 5x³ + 2x + 1.

The derivative is given by:

f'(x) = 15x² + 2.

Hence the slope at x = 8 is:

m = f'(8) = 15(8)² + 2 = 962.

The line goes through the point (8,f(8)), hence:

f(8) = 5(8)³ + 2(8) + 1 = 2577.

Hence:

y = 962x + b

2577 = 962(8) + b

b = -5119.

Hence the equation is:

y = 962x - 5119.

More can be learned about tangent lines at brainly.com/question/8174665

#SPJ1

7 0
3 years ago
Solve the inequality for x. <br><br> x-c/d &gt; y (for d &gt; 0)
Mnenie [13.5K]

Step-by-step explanation:

x-c/d>y

d(x)-d(c/d)>d(y)

dx-cd-d^2>dy

dx>dy+cd+d^2

dx>d(y+c+d)

dx/d>d(y+c+d)/d

x>d(y+c+d)/d

8 0
3 years ago
Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.
larisa86 [58]

Answer:

a) z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

b) t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

c) t_{\alpha/2}=-2.11

d) z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is \alpha=1-0.87=0.13 and \alpha/2 =0.065. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.065 and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

Part b

On this case the confidence is 92% or 0.92 so the significance level is \alpha=1-0.92=0.08 and \alpha/2 =0.04. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

df=n-1=15-1=14

We need values b,c on the t distribution with 14 degrees of freddom such that:

P(t_{(14)} or P(t_{(14)}>c)=0.04 and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

Part c

The significance level is \alpha=0.025 and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

We need a value c on the t distribution with 17 degrees of freddom such that:

P(t_{(17)}, and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values t_{\alpha/2}=-2.11

Part d

The significance level is \alpha=0.08 and \alpha/2 =0.04. On this case we know that w ehave a two tailed proportion test, so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.04 and in order to find it we can use the following code in excel:

"NORM.INV(0.04,0,1)" or "NORM.INV(1-0.04,0,1)", and we see that the critical values z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

6 0
3 years ago
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