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Goshia [24]
3 years ago
11

Graph the piecewise-defined function.

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
7 0

Answer:

We are asked to find which graph represents the graph of the piecewise-defined function g(x) given as:

g(x)= x^2-4   ;  if  x < -1

            1       ;   if  -1≤ x ≤ 1

   and   x^2+4   ; if x>1

i.e. in the region (-∞,-1) we will get a graph of a quadratic function x^2-4.

in the region [-1,1] we will get a straight line y=1.

and the region (1,∞) again we will get a graph of a quadratic function x^2+4.

Also the graph of the function is discontinuous at 1 and -1.

since the limit of the function at x=-1 and at x=1 does not exist.

As at x=-1.

Left hand limit= -3   (x^2-4; at x=-1 gives -3)

and right hand limit =1.

Whereas at x=1.

left hand limit=1

and right hand limit=5    ( x^2+4=1+4 )

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LUCKY_DIMON [66]

For the given situation we have a total of 259,459,200 permutations.

<h3>How many permutations are?</h3>

First, how we know that it is a permutation?

Because the order matters, we aren't only selecting 8 out of the 15 people, but these 8 selected also have an order (is not the same thing to finish the race first than fourth, for example).

Then we need to find the number of permutations, to do it, we need to find the numbers of options for each of the 8 positions.

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Then the total number of permutations (product between the numbers of options) is:

P = 15*14*13*12*11*10*9*8 = 259,459,200

If you want to learn more about permutations:

brainly.com/question/11732255

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2 years ago
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3 years ago
Which is a correct two column proof. Given &lt;4 and
vladimir1956 [14]

The initial statement is:    QS = SU   (1)

                                    QR = TU    (2)

 

We have to probe that:  RS = ST

 

 

Take the expression (1):                     QS       =   SU

We multiply both sides by R                (QS)R   =   (SU)R

 

 

But    (QS)R = S(QR)     Then:            S(QR)   =   (SU)R     (3)

 

From the expression (2):  QR = TU. Then, substituting it in to expression (3):

 

                                                       S(TU)   =   (SU)R     (4)

 

But  S(TU) = (ST)U  and (SU)R = (RS)U

 

Then, the expression (4) can be re-written as:

 

                                                      (ST)U    =    (RS)U

 

Eliminating U from both sides you have:     (ST) = (RS)    The proof is done.

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